I\'m trying to read user input of integer. (like cin >> nInput; in C++)
I found io:fread bif from http://www.erlang.org/doc/man/io.html, so I write code like this.
If you use string:to_integer/1, check that the value of Rest is the empty list []. The function extracts the integer, if any, from the beginning of the string. It does not assure that the full input converts to an integer.
string:to_integer(String) -> {Int,Rest} | {error,Reason}
An example:
{Int, Rest} = string:to_integer("33t").
Int. % -> 33
Rest. % -> "t"
Why check? If the user's finger slipped and hit 't' instead of 5, then the intended input was 335, not 33.
1> {ok, [X]} = io:fread("input : ", "~d").
input : 10
{ok,"\n"}
2> X.
10
3> {ok, [A,B]} = io:fread("input : ", "~d,~d").
input : 456,26
{ok,[456,26]}
That's all.
Erlang represents strings as lists of integers that are within a certain range. Therefore the input will be a number that represents the character "1" you could subtract an offset to get the actual. Number, sorry don't have a VM here to test a solution.
Try printing the number with ~w
instead of ~p
:
1> io:format("~w~n", [[10]]).
[10]
ok
2> io:format("~p~n", [[10]]).
"\n"
ok
The ~p
format specifier tries to figure out whether the list might be a string, but ~w
never guesses; it always prints lists as lists.
There are various functions in OTP to help you convert a string to an integer. If you just read a string from the user (until newline for example) you can the evaluate it with the function to_integer(String)
in the string
module:
string:to_integer(String) -> {Int,Rest} | {error,Reason}
There is also the list_to_integer(String)
BIF (Built-In Function, just call without a module) but it is not as forgiving as the string:to_integer(String)
function:
list_to_integer(String) -> int()
You will get a badarg
exception if the string does not contain an integer.