How to save both matching and non-matching from grep

Question

I use grep very often and am familiar with it\'s ability to return matching lines (by default) and non-matching lines (using the -v parameter). However, I want to be able to

Answer 1

If it does NOT have to be grep - this is a single pass split based on a pattern -- pattern found > file1 pattern not found > file2

awk '/pattern/ {print $0 > "file1"; next}{print $0 > "file2"}' inputfile

Answer 2

I had the exact same problem and I wrote a small Perl script for that [1]. It only accepts one argument: the regex to grep input on.

[1] https://gist.github.com/tonejito/c9c0bffd75d8c81483f9107c609439e1

It reads STDIN by line and checks against the given regex, matched lines go to STDOUT and not matched go to STDERR.

I made it this way because this tool sits in the middle of a pipeline and I use shell redirection to save the files on their final location.

Answer 3

Step 1 : Read the file

Step 2 : Replace spaces with a new line and save the result in a temporary file

Step 3 : Get only lines contains '_' from the temporary file and save it into multiwords.txt

Step 4 : Exclude the lines that contains '-' from the temporary file then save the result into singlewords.txt

Step 5 : Delete the temporary file

  cat file | tr ' ' '\n' > tmp.txt | grep '_' tmp.txt > multiwords.txt | grep -v '_' tmp.txt > singlewords.txt | find . -type f -name 'tmp.txt' -delete