Overload of pure virtual function

Question

I usually use pure virtual functions for those methods that are required by my code to work well. Therefore, I create interfaces and then other users implement their derived

Answer 1

An overloaded function is merely a function with the same name as another, but accepting a different set of parameters, i.e. it is a different function. It has nothing to do with whether one or more overloaded functions is virtual or not.

In the example you presented, I believe a user could overload the pure-virtual function, but only after overriding it. And you couldn't access the function from the base class directly - you'd need to cast the base class pointer to the derived class pointer.

Answer 2

You can't.

Suppose you have a Base pointer, pointing to a Derived object. Having the Base pointer, you have "access" only to the Base's interface (unless you cast to Derived pointer, but this is not what you need).

Answer 3

As pointed out by others, it just won't work.

More discretely, here is what happens

 Derived d;
 d.foo(5, 10.0); // Works as expected

 Base &b = d; // b is polymorphic
 b.foo(3,10,4); // foo(int, double, double) is not in class Base, hence compile-time resolution fails!

Answer 4

It is not overriding as the function signatures are different. According to polymorphism rule to override a function the function signatures and types should be same.

In this case these functions are different. virtual void foo(int,double)=0; virtual void foo(int, double, double);

Answer 5

Isn't overloading foo in the base class the easiest solution?

class Base
{
public:
 Base();
 virtual ~Base();
 virtual void foo(int,double)=0;
 virtual void foo(int,double,double)=0;
};

Answer 6

These 2 functions are different. The latter is not overriding the first

virtual void foo(int,double)=0;
virtual void foo(int, double, double);

The second one is new virtual function specific to derived.

If you put a override at the end the compile will complain that you are not overriding anything. This is c++11 check though.

virtual void foo(int, double, double) override;

The user can override a pure virtual function to confirm use override at the end of function to verify. In your case the second function can only be accessed using Derived pointer or type. (although it cannot be instantiated unless the pure virtual function is properly overridden and implemented, untill then it is an abstract class). Hence if it is not to be intended to be overidden further by classes that derives from Derived then making it virtual is a overhead as anyway it is not overidding the base method.