in the above image I have shown two rectangles
Try using this:
rectangelOne.x = rectangelTwo.x + rectangelTwo.width / 2;
rectangelOne.y = rectangelTwo.y + rectangleTwo.height / 2;
if your rectangleOne's pivot is correctly it should center automatically, otherwhise add this:
rectangleOne.x -= rectangleOne.width / 2;
rectangleTwo.y -= rectangleOne.height / 2;
hope this helps.
float transformValue (float x,float A,float B, float C, float D){
return C + ((x-A) * (D-C)/(B-A));
}
If:
Rectangle 1 has (x1, y1) origin and (w1, h1) for width and height, and
Rectangle 2 has (x2, y2) origin and (w2, h2) for width and height, then
Given point (x, y) in terms of Rectangle 1 coords, to convert it to Rectangle 2 coords:
xNew = ((x-x1)/w1)*w2 + x2;
yNew = ((y-y1)/h1)*h2 + y2;
Do the calculation in floating point and convert back to integer after, to avoid possible overflow.
In C#, the above would look something like:
PointF TransformPoint(RectangleF source, RectangleF destination, PointF point)
{
return new PointF(
((point.X - source.X) / source.Width) * destination.Width + destination.X,
((point.Y - source.Y) / source.Height) * destination.Height + destination.Y);
}