Delphi parse JSON array or array

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臣服心动 2021-01-12 17:26

This is the sample JSON I want to be able to parse:

[
  {
    \"a\":{
      \"username\":\"aaa\",
      \"email\":\"         


        
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  • 2021-01-12 18:06

    if you use Alcinoe TalJsonDocument it's will be simple as this :

    aJsonDoc := TalJsonDocU.create;
    aJsonDoc.loadFromFile(...);
    for i := 0 to aJsonDoc.node.childnodes.count-1 do begin
      myValue := aJsonDoc.node.childNodes[i].getchildNodeValueText(['b', 'email']); 
      if myValue <> '' then break;
    end;
    
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  • Your JSON is an array of objects, so FIds is a TJSONArray containing TJSONObject elements. And the a and b fields of those objects are themselves objects, not arrays. So FValue is TJSONArray will always be false while enumerating that array.

    Also, (FValue as TJSONArray).Items[0] as TJSONValue).Value = name is wrong, because a JSON object contains name/value pairs, but you are ignoring the names, and you are trying to enumerate the pairs as if they are elements of an array when they are really not. If you want to enumerate an object's pairs, use the TJSONObject.Count and TJSONObject.Pairs[] property. But that is not necessary in this situation since you are looking for a specific pair by its name. TJSONObject has a Values[] property for that very purpose.

    And TJSONObject.ParseJSONValue(((FValue as TJSONArray).Items[0] as TJSONValue).ToJSON) as TJSONArray is just plain ridiculous. There is no reason to convert an object back to a JSON string just to parse it again. It has already been parsed once, you don't need to parse it again.

    And lastly, FValueInner.GetValue<string>(data) is wrong, because TJSONValue does not have a GetValue() method, let alone one that uses Generics.

    Now, with that said, try something more like this instead:

    // 'name' can be 'a' or 'b'  | 'data' can be 'username' or 'email'
    function TTest.getData(const name, data: string): string;
    var
      FValue, FValueInner: TJSONValue;
    begin
      Result := '';
      for FValue in Fids do
      begin
        if (FValue is TJSONObject) then
        begin
          FValueInner := TJSONObject(FValue).Values[name];
          if FValueInner <> nil then
          begin
            if (FValueInner is TJSONObject) then
            begin
              FValueInner := TJSONObject(FValueInner).Values[data]; 
              if FValueInner <> nil then
                Result := FValueInner.Value;
            end;
            Exit;
          end;
        end;
      end;
    end;
    
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  • 2021-01-12 18:30

    For new readers looking for these answers.

    How about this function, or even simpler if you restructure the JSON data?

    function getData(JsonString: String; User: String; Field: String): String;
    var
      JSonValue: TJSonValue;
      JsonArray: TJSONArray;
      ArrayElement: TJSonValue;
      FoundValue: TJSonValue;
    begin
      Result :='';
    
      // create TJSonObject from string
      JsonValue := TJSonObject.ParseJSONValue(JsonString);
    
      // get the array
      JsonArray := JsonValue as TJSONArray;
    
      // iterate the array
      for ArrayElement in JsonArray do begin
          FoundValue := ArrayElement.FindValue(User);
          if FoundValue <> nil then begin
            Result := ArrayElement.GetValue<string>(User + '.' + Field);
            break;
          end;
      end;
    end;
    

    The problem with the sample JSON code above is that it uses the users' names "a" "b" as a JSON-key {key:data} for the users' data. In this way you can't use GetValue("a") in your search for data. Structuring your JSON data differently makes the search process a lot easier. I will later on give an example of this.

    A way to handle the given JSON data is by using FindValue so you can check if a field with key "a" or "b" exists.

    FoundValue := ArrayElement.FindValue("b");
    if FoundValue <> nil then begin
        Result := ArrayElement.GetValue<string>("b"+ '.' + "email");
        break;
    

    About the 'parsing a JSON array' question: After the data is loaded as a TJSonObject you can change the data into a TJSONArray and iterate the elements.

      JsonValue := TJSonObject.ParseJSONValue(JsonString);  
      JsonArray := JsonValue as TJSONArray;
      for ArrayElement in JsonArray do begin
        ...
    

    A working example code for the given JSON data:

    unit JsonArray1;
    
    interface
    
    uses System.JSON;
    
    function getData2(JsonString: String; User: String; Field: String): String;
    procedure Test1();
    
    implementation
    
    function getData2(JsonString: String; User: String; Field: String): String;
    var
      JSonValue: TJSonValue;
      JsonArray: TJSONArray;
      ArrayElement: TJSonValue;
      FoundValue: TJSonValue;
    begin
      Result :='';
    
      // create TJSonObject from string
      JsonValue := TJSonObject.ParseJSONValue(JsonString);
    
      // get the array
      JsonArray := JsonValue as TJSONArray;
    
      // iterate the array
      for ArrayElement in JsonArray do begin
          FoundValue := ArrayElement.FindValue(User);
          if FoundValue <> nil then begin
            Result := ArrayElement.GetValue<string>(User + '.' + Field);
            break;
          end;
      end;
    end;
    
    procedure Test1();
    var
      DataBase: String;
      EmailAddress : String;
      Username: String;
    begin
      DataBase := '[  {"a" : {"username":"aaa","email":"aaa@gmail.com"}},' +
                     '{"b" : {"username":"bbb","email":"bbb@gmail.com"}}  ]';
    
      EmailAddress := getData2(DataBase, 'b', 'email');
      Username := getData2(DataBase, 'a', 'username');
    
    end;
    
    end.
    

    As already mentioned, restructuring the JSON data with proper keys makes the code to find data more simple. Because there is a 1 on 1 relation between the users' data "a":{}, "b":{} it's easy to introduce a 'user' key. Also adding a 'users' key to the array results in all data having keys.

      '{"users" : [{ "user":"a", "username":"aaa","email":"aaa@gmail.com"},' +
                  '{ "user":"b", "username":"bbb","email":"bbb@gmail.com"}]}';
    

    When you iterate the users, you can now use GetValue with the new "user" key.

      if ArrayElement.GetValue<String>('user') = 'b' then begin
        Result := ArrayElement.GetValue<String>('email');
    

    By giving the array a key you can now get the array with:

    JsonArray := JsonValue.GetValue<TJSONArray>('users');
    

    A working example code for the restructured JSON data:

    unit JsonArray2;
    
    interface
    
    uses System.JSON;
    
    function getData2(JsonString: String; User: String; Field: String): String;
    procedure Test2();
    
    implementation
    
    function getData2(JsonString: String; User: String; Field: String): String;
    var
      JSonValue: TJSonValue;
      JsonArray: TJSONArray;
      ArrayElement: TJSonValue;
      FoundValue: TJSonValue;
    begin
      Result :='';
    
      // create TJSonObject from string
      JsonValue := TJSonObject.ParseJSONValue(JsonString);
    
      // get the array
      JsonArray := JsonValue.GetValue<TJSONArray>('users');
    
      // iterate the array
      for ArrayElement in JsonArray do begin
          if ArrayElement.GetValue<String>('user') = User then begin
            Result := ArrayElement.GetValue<String>(Field);
            break;
          end;
      end;
    end;
    
    procedure Test2();
    var
      DataBase: String;
      EmailAddress : String;
      Username: String;
    begin
      DataBase := '{"users" : [{ "user":"a", "username":"aaa","email":"aaa@gmail.com"},' +
                              '{ "user":"b", "username":"bbb","email":"bbb@gmail.com"}]}';
    
      EmailAddress := getData2(DataBase, 'b', 'email');
      Username := getData2(DataBase, 'a', 'username');
    
    end;
    
    end.
    
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