I am using below code while inserting a row into database(oracle 10g xe,jar: ojdbc14.jar)
String sql = \"INSERT INTO SPONSOR_TB(ID,NAME,INDUSTRY_TYPE,IS_REPO
for me this issue happened when i try to set null value on timestamp column. I changed the value timestamp(0). This seems to me a driver issue. I was using oracle 10g / ojdbc14.jar / oracle.jdbc.OracleDriver
java.sql.SQLException: Invalid column type
at oracle.jdbc.dbaccess.DBError.throwSqlException(DBError.java:134)
at oracle.jdbc.dbaccess.DBError.throwSqlException(DBError.java:179)
at oracle.jdbc.dbaccess.DBError.throwSqlException(DBError.java:269)
at oracle.jdbc.driver.OracleStatement.get_internal_type(OracleStatement.java:6433)
at oracle.jdbc.driver.OraclePreparedStatement.setNull(OraclePreparedStatement.java:1354)
You are getting this exception because you are using JdbcTemplate
instead of NamedParameterJdbcTemplate
. MapSqlParameterSource
works with NamedParameterJdbcTemplate
.
You might want to try using strings instead of characters for your CHAR(1) Y/N fields.
Try changing your code to:
paramSource.addValue("NAME1",sponsor.getName(), Types.VARCHAR);
paramSource.addValue("INDUSTRY_TYPE", sponsor.getIndustryType(), Types.INTEGER);
paramSource.addValue("IS_NOT_SOLICITE", sponsor.getNotSoliciteFlag()?'Y':'N', Types.CHAR);
paramSource.addValue("IS_REPORTING_SPONSOR", sponsor.getReportingFlag()?'Y':'N', Types.CHAR);
Though it is too late, today I found the same issue. I tried all of the above options which were provided by the other members, but no luck. What I found was, to add a char column in where clause I was providing the java.lang.char in that space.
Suppose my query looks like this - SELECT * FROM app_config WHERE enable = :enable;
, where the 'enable' column is char(1) column in DB. So while passing the parameter in namedparameterJdbcTemplate, I was passing a java char as 'Y'
, which was causing the error.
In order to solve that I passed normal java string as the parameter value in the namedparameterJdbcTemplate like "Y"
and BANG!!! It works fine. Also I need not to provide the Types
in MapSqlParameterSource. So my ultimately code looks like below -
protected String getConfigValue(String configKey, String enable) throws BusinessException {
String value = "";
try {
if (StringUtils.isNotBlank(configKey)) {
MapSqlParameterSource parameters = new MapSqlParameterSource();
parameters.addValue(ApplicationDaoConstants.CONFIG_KEY, configKey); // This is the VARCHAR column in DB
parameters.addValue(ApplicationDaoConstants.ENABLE, enable); // This is the character column in DB
value = nmJdbcTmplt.query(AppConfigSQL.GET_CONFIG_VALUE, parameters, rs -> {
if (rs.next()) {
return rs.getString(ApplicationDaoConstants.CONFIG_VALUE);
}
return "";
});
}
} catch (Exception e) {
log.error("Exception occured while accessing app_config ", e);
throw new BusinessException(ApplicationConstants.ERROR_ACCESSING_DATABASE);
}
return value;
}
I hope this could help others. Thanks!
In my case I was providing an Enumeration datatype instead of a datatype compatible with VARCHAR2 in database (like String ).
My query was like :
private static final String QUERY ="SELECT res.id, FROM result res " +
"WHERE res.country = :resCountry ";
And at the time of passing the parameter resCountry, I did like this:
List<Map<String, Object>> listResult = jdbcTemplate.queryForList(QUERY,Country.US);
Now the complaint/exception came from the fact that Country.US was of type Enumeration Country
I did the following change to make it work.
List<Map<String, Object>> listResult = jdbcTemplate.queryForList(QUERY,Country.US.name());
After this change it worked fine.