Sort one array the same way as another array JavaScript

Question

I have 2 arrays:

[2, 4, -2, 4, 1, 3]
[\"a\", \"b\", \"c\", \"d\", \"e\", \"f\"]

and I want them to be sorted by the numerical array:

<

Answer 1

You can do this in a single line by associating your two arrays and then ordering the items:

const x = ["a", "b", "c", "d", "e", "f"]   
const y = [2, 4, -2, 4, 1, 3]

const result = y.map((val, index)=>({x:x[index], y:val})).sort((a,b)=>a.y-b.y).map(v=>v.x)

// -> ["c", "e", "a", "f", "b", "d"]

Answer 2

I would recommend storing the entire thing in a Map. That way, you can independently sort the first array however you want and then use those values as keys to call respective value of second array.

Answer 3

You could sort the keys of the first array based on their value. This will return an array with indices of the array sorted based on the value of numbers array. Then use map to get the sorted values based on the indices

const numbers = [2, 4, -2, 4, 1, 3],
      alphabets = ["a", "b", "c", "d", "e", "f"]

const keys = Array.from(numbers.keys()).sort((a, b) => numbers[a] - numbers[b])

const sortedNumbers = keys.map(i => numbers[i]),
      sortedAlphabets = keys.map(i => alphabets[i])

console.log(
  sortedNumbers,
  sortedAlphabets
)

Answer 4

A standard method is to take the indices of the key array for sorting and sort the indices as pattern for all other arrays by taking the index and the value from the key array.

At the end map the sorted arrays.

var array1 = [2, 4, -2, 4, 1, 3],
    array2 = ["a", "b", "c", "d", "e", "f"],
    indices = [...array1.keys()].sort((a, b) => array1[a] - array1[b]);

[array1, array2] = [array1, array2].map(a => indices.map(i => a[i]));

console.log(...array1);
console.log(...array2);