I have a list like this:
paths = [[\'test_data\', \'new_directory\', \'ok.txt\'], [\'test_data\', \'reads_1.fq\'], [\'test_data\', \'test_ref.fa\']]
<
can try this also,
list1=['a','b','c','d']
list2=[1,2,3,4]
we want to zip these two lists and create a dictionary dict_list
dict_list = zip(list1, list2)
dict(dict_list)
this will give:
dict_list = {'a':1, 'b':2, 'c':3, 'd':4 }
Yes it is possible, use collections.defaultdict
:
>>> from collections import defaultdict
>>> dic = defaultdict(list)
>>> lis = [['test_data', 'new_directory', 'ok.txt'], ['test_data', 'reads_1.fq'],
for item in lis:
key = "/".join(item[:-1])
dic[key].append(item[-1])
...
>>> dic
defaultdict(<type 'list'>,
{'test_data': ['reads_1.fq', 'test_ref.fa'],
'test_data/new_directory': ['ok.txt']})
using simple dict
:
>>> dic = {}
>>> for item in lis:
key = "/".join(item[:-1])
dic.setdefault(key, []).append(item[-1])
...
>>> dic
{'test_data': ['reads_1.fq', 'test_ref.fa'],
'test_data/new_directory': ['ok.txt']}