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Loop from A to Z in jQuery

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星月不相逢
星月不相逢 2021-01-12 14:20

How can I loop from A to Z? I\'d like to populate a select menu with the letters of the alphabet, eg
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  • 梦谈多话
    2021-01-12 14:41

    One-liner

    [..."ABCDEFGHIJKLMNOPQRSTUVWXYZ"].map(v=>`<option>${v}</option>`).join('')
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  • 半阙折子戏
    2021-01-12 14:46

    Use char codes: JavaScript Char Codes

    for (var i = 65; i <= 90; i++) {
    $('#select_id_or_class').append('<option>' + String.fromCharCode(i) + '</option>');
}
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  • 感情败类
    2021-01-12 15:05

    You can avoid having numbers like 65 in your code if you just use charCodeAt() and fromCharCode().

    Print letters from a to z:

    for(let i = 'a'.charCodeAt(0); i <= 'z'.charCodeAt(0); i++) {
  $('#select_id_or_class').append(
    '<option>' + String.fromCharCode(i) + '</option>'
  );
}

    Or:

    const aCharCode = 'a'.charCodeAt(0);

for(let i = aCharCode; i <= (aCharCode + 26); i++) {
  $('#select_id_or_class').append(
    '<option>' + String.fromCharCode(i) + '</option>'
  );
}

    If you want the uppercase characters, replace 'a'.charCodeAt(0) with 'A'.charCodeAt(0)

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  • 佛祖请我去吃肉
    2021-01-12 15:06

    This answer demonstrates the nice idea that you do not need a hardcoded string. In short:

    for (i = 65; i <= 90; i++) { arr[i-65] = String.fromCharCode(i).toLowerCase(); }

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