How do I check if a string contains a number

Question

I need to check if a string contains a number. Any number. Not wether or not the string IS a number, but if it contains one.

Examples:

\'test\' = no numbers.

Answer 1

I would try using regex. Like:

select regexp_instr('%[0-9]%',@str1) from table_name;

Cheers --Jocke

Answer 2

Using a regular expression:

SELECT *
FROM test
WHERE REGEXP_LIKE(testcol, '[[:digit:]]');

Not using regular expressions:

SELECT *
FROM test
WHERE testcol LIKE '%0%'
    OR testcol LIKE '%1%'
    OR testcol LIKE '%2%'
    OR testcol LIKE '%3%'
    OR testcol LIKE '%4%'
    OR testcol LIKE '%5%'
    OR testcol LIKE '%6%'
    OR testcol LIKE '%7%'
    OR testcol LIKE '%8%'
    OR testcol LIKE '%9%'

Answer 3

This is the technique that I use to detect if a string contains a number:

select LAST_NAME, 'contains a number'
  FROM names
 where translate(LAST_NAME, '0123456789', '') <> LAST_NAME

That works by translating the digits to empty string. If the string remains the same, then it could not have contained digits.

This technique also works to test if a string is all numbers

select TEL_NUMBER, 'is all numbers'
  FROM names
 where trim(translate(TEL_NUMBER, '-0123456789', '')) = ''

For the telephone number I included a dash because telephone numbers typically contain dashes.

Answer 4

I sometimes use REGEXP_INSTR in NetSuite saved searches since the SQL functions are limited. It returns a zero if no numbers are found, or the starting position of the first number found in the string:

REGEXP_INSTR(my_var, '[[:digit:]]')

This example returns zero:

REGEXP_INSTR('test', '[[:digit:]]')

This example returns a number greater than zero since it found a number:

REGEXP_INSTR('test2', '[[:digit:]]')