How to get first letter of every word using regex in PHP

Question

I have a string variable and I want to get the first letter of every word of it. I want the end result to be an array of first letters.

$language = \'Sample          


        

Answer 1

First of all use preg_match_all for this, and secondly you don't need the + quantifier:

$language = 'Sample Language';
preg_match_all('/\b\w/', $language, $match);
print_r($match);

• \b: Matches a word boundary, a word boundary is a position that separates a word character from a non-word character. Word characters are usually [a-zA-Z0-9_].
• \w: Matches a word character.
• \b\w Matches a word character that is at a word boundary position, in this case right after the space or the start-of-string that separates the words.

In case you want camel case situations then you can combine the previous expression with another one like this:

\b\w|(?<=\p{Ll})\p{Lu}

The second part of the expression, namely (?<=\w)\p{Lu} should match any word character if it is an uppercase character \p{Lu} following a lowercase one \p{Ll} which should cover the camel case situation, the original expressions covers the situation when a hyphen - is used to separate the two words.

Regex101 Demo

Answer 2

Can you try this,

    $language = 'Sample Language';

    $language = explode(" ", $language);

    foreach ($language as $value) {
        echo $firstLetter = $value[0];
    }