Get the __file__ of the function one level up in the stack

Question

I\'ve found that I\'m using this pattern a lot :

os.path.join(os.path.dirname(__file__), file_path)

so I\'ve decided to put in a function i

Answer 1

This should do it:

inspect.getfile(sys._getframe(1))

sys._getframe(1) gets the caller frame, inspect.getfile(...) retrieves the filename.