Including a whole directory in PHP or Wildcard for use in PHP Include?

Question

I have a command interpreter in php. It lives inside the commands directory and needs access to every command in the command file. Currently I call require once on each co

Answer 1

It's 2015 now, so you're most likely running PHP >= 5. If so, as mentioned a couple of times above, PHP's autoload capability is a good solution, probably the best. It was created specifically so you won't have to write a utility function for auto loading. However, as mentioned in the PHP docs, __autoload is no longer recommend and may be depreciated in future versions. As long as you're using PHP >= 5.1.2, use spl_autoload_register instead.

Answer 2

Why do you want to do that? Isn't it a better solution to only include the library when needing it to increase speed and reduce footprint?

Something like this:

Class Interpreter 
{
    public function __construct($command = null)
    {
        $file = 'Command'.$command.'.php';

        if (!file_exists($file)) {
             throw new Exception('Invalid command passed to constructor');
        }

        include_once $file;

        // do other code here.
    }
}

Answer 3

You can't require_once a wildcard, but you can programmatically find all the files in that directory and then require them in a loop

foreach (glob("*.php") as $filename) {
    require_once($filename) ;
}

http://php.net/glob

Answer 4

You can include all files using foreach ()
Store all files name in array.

$array =  array('read','test');

foreach ($array as $value) {
    include_once $value.".php";
}

Answer 5

foreach (glob("*.php") as $filename) {
    require_once $filename;
}

I'd be careful with something like that though and always prefer "manually" including files. If that's too burdensome, maybe some refactoring is in order. Another solution may be to autoload classes.