unable to get $_SESSION variable

Question

In Log-in.php I have

  $email=$_POST[\'email\']; 
  $pass=$_POST[\'         


        

Answer 1

Set this code in login.php :

session_start();
$email = $_POST['email'];
$pass = $_POST['pass'];
$_SESSION['type'] = 'user';
$_SESSION['email'] = $email;
$_SESSION['pass'] = $pass;
header('location:./connect.php');

And this one in connect.php :

session_start();
@mysql_connect('localhost', 'root', '') or die("ERROR in SERVER");
@mysql_select_db('module') or die("ERROR IN DATABASE");
$_SESSION['start'] = time(); // taking now logged in time
if (!isset($_SESSION['expire'])) {
    $_SESSION['expire'] = $_SESSION['start'] + (60 * 60);
}
$now = time(); // checking the time now when home page starts
if ($now > $_SESSION['expire']) {
    session_destroy();
    header('location:./login/login.php');
}
if (isset($_SESSION['email']) && !empty($_SESSION['email']) &&
        isset($_SESSION['pass']) && !empty($_SESSION['pass']) &&
        isset($_SESSION['type']) && !empty($_SESSION['type'])) {

    $email = $_SESSION['email'];
    $pass = $_SESSION['pass'];
    $type = $_SESSION['type'];

    // admin login //
    if ($type == 'admin') {
        $admin = mysql_query("SELECT * FROM `admin` WHERE `email`='$email'");
        $res = mysql_fetch_array($admin);
        if ($email == "" || $pass == "" || $email != $res['email'] || $pass != $res['pass']) {
            session_destroy();
            header('location:./login/login.php');
        }
    }

    // user login //
    if ($type == 'user') {
        $user = mysql_query("SELECT `id` FROM `users` WHERE `email`='$email' AND `status`='1'");
        $useres = mysql_fetch_array($user);
        // $trail = $useres['date'];
        //  $time = explode("/",$trail);
        if ($email != $useres['email'] || $pass != $useres['pass']) {
            session_destroy();
            header('location:./login/login.php');
        }
    }

    // agent login //
    if ($type == 'agent') {
        $agent = mysql_query("SELECT `id` FROM `sale_agents` WHERE `email`='$email'");
        $agentres = mysql_fetch_array($agent);
        if ($email != $agentres['email'] || $pass != $agentres['pass']) {
            session_destroy();
            header('location:./login/login.php');
        }
    }
} else {
    header('location:./login/login.php');
}

I hope this will help you.

Answer 2

session_start();

$_SESSION["user"] = $result['full_name'];
$_SESSION["user_id"] = $result['user_id'];
$_SESSION["website_type"] = $result['user_id'];

// this is my code ... // i cant access in another page ..

// second page enter code here session_start(); // print_r($_SESSION);

    echo $_SESSION['user'];
    echo $_SESSION['user_id'];
    echo $_SESSION['website_type'];

Answer 3

Sessions Step By Step

1. Defining session before everything, No output should be before that, NO OUTPUT

   <?php
   session_start();
   ?>
   

2. Set your session in a page and then you have access in that, for example this is page 1.php

   <?php
      //This is page 1 and then we will use session that defined from this page:
       session_start();
       $_SESSION['email]='email@example.com';
   ?>
   

3. Using and Getting session in 2.php

    <?php
      //In this page I am going to use session:
     session_start();
     if($_SESSION['email']){
     echo 'Your Email Is Here!  :) ';
     }
    ?>
   

NOTE: Comments don't have output.

---

Maybe answer to your question:

I think you are not setting session, and because of that PHP doesn't know that session variable.

Your login should be like this

  <?php
  session_start();
  $email=$_POST['email']; 
  $pass=$_POST['pass'];
  $_SESSION['type'] = 'user';
  $_SESSION['email'] = $email; 
  $_SESSION['pass']=$pass; 
  header('location:./connect.php');
  ?>