Cron expression to run job twice a day at different time?

Question

I have one job that needs to be execute twice a day at different time . e.g. 10:00 and 15:30. How can i achieve this ?

I am confuse because minute is different for b

Answer 1

You can set values for each job:

0 10 * * * job

30 15 * * * job

Here is more info:

*    *    *    *    *  command to be executed
┬    ┬    ┬    ┬    ┬
│    │    │    │    │
│    │    │    │    │
│    │    │    │    └───── day of week (0 - 7) (0 or 7 are Sunday, or    use names)
│    │    │    └────────── month (1 - 12)
│    │    └─────────────── day of month (1 - 31)
│    └──────────────────── hour (0 - 23)
└───────────────────────── min (0 - 59)

Wikipage about cron https://en.wikipedia.org/wiki/Cron

Answer 2

I have tried using 0 1,6 * * ? * expression for my request - to schedule job during 1am and 6am every day. So for your request to schedule 10:00 and 15:00 time, i believe the following cron expression should work. Please give a try and let me know 0 10,15 * * ? *

Answer 3

Try following which you will get closest in one expression

0 0 10,15/12 * * ?

this will run 10:00 and 15:00.