How to overload the indirection operator? (C++)

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既然无缘
既然无缘 2021-01-12 01:30

I\'m trying to create an iterator class as a member-class for a list class, and am trying to overload the indirection operator (*) to access the list it\'s pointing to:

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  • 2021-01-12 01:51

    You have two problems here; the first is that you have accidentally overloaded the multiplication operator and not the dereferencing operator; the second is that you haven't returned a reference type.

    The first issue comes about as a result of the number of parameters. Every non-static member function of a class has an additional "hidden" parameter: this. this is, of course, the pointer to the object the function is being invoked on. As a result, you have actually declared a version of the operator taking two parameters. By removing the second iterator parameter and operating on this, you will be overloading the unary * and not the binary one.

    The second issue is a minor one of return type; you are returning a copy to the original object and not the original object itself. Declare the return type as T& to return a reference.

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  • 2021-01-12 01:54

    You overloaded the multiply operator. Take the parameter out to make it an indirection operator.

    template<class T>
    T list<T>::iterator::operator*()
    {
        return ((this->lstptr)->current)->data;
    }
    

    You should also have it return a reference if you want code like *IT = 3; to compile.

    template<class T>
    T& list<T>::iterator::operator*()
    {
        return ((this->lstptr)->current)->data;
    }
    
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