I just start to learn how to build batch file. ( on the windows 7 environment)
I want to build the batch file which is able to run .exe files sequentially .
start MyDriver.exe
start YouDriver.exe
start MySoftware.exe
If you want the batch file in a different dir you would have to do:
cd D:\
start MyDriver.exe
start YouDriver.exe
start MySoftware.exe
If you want a more flexible system:
echo Welcome to EXE starter!
set /p dir = DIR:
set /p exe = EXE1:
set /p exe1 = EXE2:
set /p exe 2 = EXE3:
cd DIR
start exe
start exe1
start exe2
There you go!
To do it squentially:
call YouDriver.exe
call MeDriver.exe
call Mysoftware.exe
call
will halt the batch file until program has closed.
Try and put it in the same directory of the files you want to run. If you can't, use cd C:\Directory\Name to change it to the directory where the MyDriver.exe file is. Then just do MyDriver.exe- you don't need a call or start statement.
MyDriver.exe
YouDriver.exe
MySoftware.exe
use cd at the start if you neeed to.
This will start each file and wait for it to complete and then launch the next one.
@echo off
start "" /w /b "d:\MyDriver.exe"
start "" /w /b "d:\YouDriver.exe"
start "" /w /b "d:\Mysoftware.exe"
You actually don't need to do anything special to make this happen; batch files are synchronous by default, so execution of the batch file will pause when an executable is launched, and resume when it exits. Something as simple as this should do:
@echo off
REM "@echo off" prevents each line from being printed before execution,
REM and is optional
REM "REM" introduces a comment line
D:\MyDriver.exe
D:\YouDriver.exe
D:\MySoftware.exe
Of course, if you're interested in checking the return values of the programs, to see whether they succeeded or failed to install (assuming the installer provides that information), then things become slightly more complicated; if that's what you need, mention it in a comment, and I'll expand my answer accordingly.