My priority queue declared as:
std::priority_queue<*MyClass> queue;
class MyClass {
bool operator<( const MyClass* m ) const;
}
The operator <() you have provided will compare a MyClass object with a pointer to a MyClass object. But your queue contains only pointers (I think). You need a comparison function that takes two pointers as parameters.
All this is based on some suppositions - please post your actual code, using copy and paste.
Not sure about the priority queue stuff because I've never used it but to do a straight sort, you can do this:
class A
{
friend struct ComparePtrToA;
public:
A( int v=0 ):a(v){}
private:
int a;
};
struct ComparePtrToA
{
bool operator()(A* a1, A* a2) {return a1->a < a2->a;}
};
#include <vector>
#include <algorithm>
int _tmain(int argc, _TCHAR* argv[])
{
vector<A*> someAs;
someAs.push_back(new A(1));
someAs.push_back(new A(3));
someAs.push_back(new A(2));
sort( someAs.begin(), someAs.end(), ComparePtrToA() );
}
Note the memory leaks, this is only an example...
Further note: This is not intended to be an implementation of priority queue! The vector is simply an example of using the functor I created to compare two objects via their pointers. Although I'm aware of what a priority queue is and roughly how it works, I have never used the STL features that implement them.
Update: I think TimW makes some valid points. I don't know why he was downvoted so much. I think my answer can be improved as follows:
class A
{
public:
A( int v=0 ):a(v){}
bool operator<( const A& rhs ) { return a < rhs.a; }
private:
int a;
};
struct ComparePtrToA
{
bool operator()(A* a1, A* a2) {return *a1 < *a2;}
};
which is cleaner (especially if you consider having a container of values rather than pointers - no further work would be necessary).
Since your priority_queue
contains only pointer values, it will use the default comparison operator for the pointers - this will sort them by address which is obviously not what you want. If you change the priority_queue
to store the class instances by value, it will use the operator you defined. Or, you will have to provide a comparison function.
Give the que the Compare functor ptr_less.
If you want the ptr_less to be compatible with the rest of the std library (binders, composers, ... ):
template<class T>
struct ptr_less
: public binary_function<T, T, bool> {
bool operator()(const T& left, const T& right) const{
return ((*left) <( *right));
}
};
std::priority_queue<MyClass*, vector<MyClass*>, ptr_less<MyClass*> > que;
Otherwise you can get away with the simplified version:
struct ptr_less {
template<class T>
bool operator()(const T& left, const T& right) const {
return ((*left) <( *right));
}
};
std::priority_queue<MyClass*, vector<MyClass*>, ptr_less > que;