With
preg_match($pattern, $subject, $matches, PREG_OFFSET_CAPTURE);
is it possible to search a string in reverse? ie. return the position
preg_match
does not support reverse searching because it is not neccessary.
You can create a RegExp that contains a greedy (that is default) lookahead that matches anything (like (?<=.*)stuff
). This way you should get the last occurence of your match.
detailed information from official documentation here: preg_match
"Greedy" is the key word here. * is by default greedy *? limits greediness to the bare minimum.
So the solution is to use the combination, e.g. (searching for last period followed by a whitespace):
/^.*\.\s(.*?)$/s
I did not understand exactly what you want, because it depends on how many groups will be captured, I made a function to capture the offset of the last capture according to the group number, in my pattern, have 3 groups: the first group, full capture and the other two groups, sub-groups.
Pattern sample code:
$pattern = "/<a[^\x3e]{0,}href=\x22([^\x22]*)\x22>([^\x3c]*)<\/a>/";
HTML sample code:
$subject = '<ul>
<li>Search Engines</li>
<li><a href="https://www.google.com/">Google</a></li>
<li><a href="http://www.bing.com/">Bing</a></li>
<li><a href="https://duckduckgo.com/">DuckDuckGo</a></li>
</ul>';
My Function, it captures the offset of the last element and you have the possibility to indicate the number of matching:
function get_offset_last_match( $pattern, $subject, $number ) {
if ( preg_match_all( $pattern, $subject, $matches, PREG_OFFSET_CAPTURE ) == false ) {
return false;
}
return $matches[$number][count( $matches[0] ) - 1][1];
}
You can get detailed information about preg_match_all here on official documentation.
Using my pattern for example:
0 => all text
1 => href value
2 => innerHTML
echo '<pre>';
echo get_offset_last_match( $pattern, $subject, 0 ) . PHP_EOL; // all text
echo get_offset_last_match( $pattern, $subject, 1 ) . PHP_EOL; // href value
echo get_offset_last_match( $pattern, $subject, 2 ) . PHP_EOL; // innerHTML
echo '</pre>';
die();
Output is:
140
149
174
My function (text):
function get_text_last_match( $pattern, $subject, $number ) {
if ( preg_match_all( $pattern, $subject, $matches, PREG_OFFSET_CAPTURE ) == false ) {
return false;
}
return $matches[$number][count( $matches[0] ) - 1][0];
}
Sample code:
echo '<textarea style="font-family: Consolas: font-size: 14px; height: 200px; tab-size: 4; width: 90%;">';
echo 'ALL = ' . get_text_last_match( $pattern, $subject, 0 ) . PHP_EOL; // all text
echo 'HREF = ' . get_text_last_match( $pattern, $subject, 1 ) . PHP_EOL; // href value
echo 'INNER = ' . get_text_last_match( $pattern, $subject, 2 ) . PHP_EOL; // innerHTML
echo '</textarea>';
Output is:
ALL = <a href="https://duckduckgo.com/">DuckDuckGo</a>
HREF = https://duckduckgo.com/
INNER = DuckDuckGo
PHP doesn't have a regex method that search a string from right to left (like in .net). There are several possible recipes to solve that (this list isn't exhaustive, but may provide ideas for your own workaround ):
PREG_SET_ORDER
flag and end($matches) will give you the last match set\K
to start the match result at the position you want. Once the end of the string is reached, the regex engine will backtrack until it finds a match.Examples with the string $str = 'xxABC1xxxABC2xx'
for the pattern /x[A-Z]+\d/
way 1: find all matches and displays the last.
if ( preg_match_all('/x[A-Z]+\d/', $str, $matches, PREG_SET_ORDER) )
print_r(end($matches)[0]);
demo
way 2: find the first match of the reversed string with a reversed pattern, and displays the reversed result.
if ( preg_match('/\d[A-Z]+x/', strrev($str), $match) )
print_r(strrev($match[0]));
demo
Note that it isn't always so easy to reverse a pattern.
way 3: Jumps from x to x and checks with the negative lookahead if there's no other x[A-Z]+\d
matches from the end of the string.
if ( preg_match('/x[A-Z]+\d(?!.*x[A-Z]+\d)/', $str, $match) )
print_r($match[0]);
demo
variants:
With a lazy quantifier
if ( preg_match('/x[A-Z]+\d(?!.*?x[A-Z]+\d)/', $str, $match) )
print_r($match[0]);
or with a "tempered quantifier"
if ( preg_match('/x[A-Z]+\d(?=(?:(?!x[A-Z]+\d).)*$)/', $str, $match) )
print_r($match[0]);
It can be interesting to choose between these variants when you know in advance where a match has the most probabilities to occur.
way 4: goes to the end of the string and backtracks until it finds a x[A-Z]+\d
match. The \K
removes the start of the string from the match result.
if ( preg_match('/^.*\Kx[A-Z]+\d/', $str, $match) )
print_r($match[0]);
way 4 (a more hand-driven variant): to limit backtracking steps, you can greedily advance from the start of the string, atomic group by atomic group, and backtrack in the same way by atomic groups, instead of by characters.
if ( preg_match('/^[^x]*+(?>x[^x]*)*\Kx[A-Z]+\d/', $str, $match) )
print_r($match[0]);