Python - Increment Characters in a String by 1

Question

I\'ve searched on how to do this in python and I can\'t find an answer. If you have a string:

>>> value = \'abc\' 

How would you

Answer 1

Very simple four line piece of code:

finalMessage=""
for x in range (0,len(value)):
    finalMessage+=(chr(ord(value[x])+1))
print(finalMessage)

It goes through each letter in the string and adds one to it, but this doesn't work with "z", so you could do:

value="abc testing testing, or sdrshmf"
finalMessage=""
for x in range(0,len(value)):
    if ord(value[x]) in range(97,123):
        finalMessage+=(chr(((ord(value[x])-96)%26)+97))
    elif ord(value[x]) in range(65,91):
        finalMessage+=(chr(((ord(value[x])-64)%26)+65))
    else:
        finalMessage+=value[x]
print(finalMessage)

Answer 2

You could use a generator expression with ''.join() as follows:

In [153]: value = 'abc'

In [154]: value_altered = ''.join(chr(ord(letter)+1) for letter in value)

In [155]: value_altered
Out[155]: 'bcd'

The generator iterates over each letter in the string value and increments it by one using the chr(ord(letter)+1) methodology suggested in your question. It then uses ''.join() to convert the letters in the generator back into a string.

Answer 3

As gtllambert beat me to my original answer, I am posting an alternative solution. You can also use map and a lambda expression to achieve the same. The lambda expression uses chr and ord to increment each character by one and chr is used to convert it back to a character.

value = 'abc'
''.join(map(lambda x:chr(ord(x)+1),value))

Answer 4

value = 'abc'
newVar=(chr(ord(value[0])+1))
newVar1=(chr(ord(value[1])+1))
newVar2=(chr(ord(value[2])+1))
value=newVar+newVar1+newVar2
print(value)

Here is what I came up with can't believe it actually worked thanks for the challenge using python 3