How to Keep Track of row index when JTable has been sorted by the user?

Question

I have a JTable which has 1st row blank. Now when I sort the table based on a column by clicking on that column then the blank row goes at the bottom. If I insert something

Answer 1

JTable.convertRowIndexToView() will return you an index of the row in the view based on its index in the model. JTable.convertRowIndexToModel() will do the opposite.

Answer 2

SOLUTION 1

There is some issue when using jTable1.convertRowIndexToModel(jTable1.getSelectedRow()) if you sort the values according to date or time will return incorrect values from the convertRowIndexToView(0) therefore use convertRowIndexToModel(0).

SOLUTION 2

This will retrieve from the new model when sorted.

jTable1.getValueAt(jTable1.getSelectedRow(), 0);

This will retrieve value according to the original index even when sorted.

((DefaultTableModel)jTable1.getModel()).getValuAt(jTable1.getSelectedRow(), 0);

Answer 3

Assuming you're using the TableRowSorter stuff added in Java 6, I think what you need to look at are the methods convertRowIndexToModel and convertRowIndexToView in the RowSorter Class. You'd do something like

table.getRowSorter().convertRowIndexToView(0)

to find out which visible row index is actually row index 0 from your model.

Edit: As Tulskiy pointed out in the comments, this may cause a NullPointerException if no row sorter is assigned to the table. Better to use the methods directly on JTable instead, e.g. table.convertRowIndexToView(0)