How to concat two char * in C?

Question

I receive a char * buffer which have the lenght of 10. But I want to concat the whole content in my struct which have an variable char *.

typedef struct{
            


        

Answer 1

You can use strcat(3) to concatenate strings. Make sure you have allocated enough space at the destination!

Note that just calling strcat() a bunch of times will result in a Schlemiel the Painter's algorithm. Keeping track of the total length in your structure (or elsewhere, if you prefer) will help you out with that.

Answer 2

I am not clear. Do you want:

• to concatenate every one of the 10 character buffers you receive into one array, pointed at by one real[0].buffer, or
• do you want each 10 character buffer to be pointed at by a different real[i].buffer, or
• something else?

You will need to allocate enough space for the copy of the buffer:

#include <stdlib.h>
//...
int size = 10+1; // need to allocate enough space for a terminating '\0'
char* buff = (char *)malloc(size);   
if (buff == NULL) {
    fprintf(stderr, "Error: Failed to allocate %d bytes in file: %s, line %d\n,
                     size, __FILE__, __LINE__ );
    exit(1);
}
buff[0] = '\0';    // terminate the string so that strcat can work, if needed
//...
real[i].buffer = buff;  // now buffer points at some space
//...
strncpy(real[i].buffer, buffer, size-1);

Answer 3

In general, do the following (adjust and add error checking as you see fit)

// real[i].buffer += buffer; 

   // Determine new size
   int newSize = strlen(real[i].buffer)  + strlen(buffer) + 1; 

   // Allocate new buffer
   char * newBuffer = (char *)malloc(newSize);

   // do the copy and concat
   strcpy(newBuffer,real[i].buffer);
   strcat(newBuffer,buffer); // or strncat

   // release old buffer
   free(real[i].buffer);

   // store new pointer
   real[i].buffer = newBuffer;