Is it possible to have a non-rectangular div?

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I need to shape ONE div tag in the following shape:

Is it possible to make it cross browser? I don\'t necessarily need rounded

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南笙

2021-01-11 14:33

You can either use a map or use 2 divs and alter the borders so it looks like one shape.

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灰色年华

2021-01-11 14:33

Use multiple divs, as others have suggested.

http://jsfiddle.net/thomas4g/7B5MA/14/

Keep in mind that it'll be very hard to flow content in this.

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野的像风

2021-01-11 14:44

 <!DOCTYPE HTML>
 <html>
 <head>

 <style>
 html{height: 100%; width: 100%;}
 body{height: 100%; width: 100%;}

 #wrapper{
 position: relative;
 top: 50px;
 right: 25%;
 width: 565px;
 height: 440px;
 margin: 0 auto;
 padding: 0px;
 }
 #left{
 position: absolute;
 width: 100px;
 height: 50px;
 border: 2px solid black;
 border-right: none;
 -moz-border-radius-bottomleft: 10px; 
 border-bottom-left-radius: 10px;
 -moz-border-radius-topleft: 10px;
 border-top-left-radius: 10px;
 background-color: #ffffff;
 }
 #right{
 position: absolute;
 left: 100px;
 width: 440px;
 height: 440px;
 border: 2px solid black;
 -moz-border-radius: 10px;
 -moz-border-radius-topleft: 0px;
 border-top-left-radius: 0px;
 border-radius: 10px;
 padding-left: 25px;
 }
 </style>


 <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.6.1/jquery.min.js">    </script>
 <script type="text/javascript">
  $(document).ready(function(){
  $('#wrapper').hover(
   function () {
  $(this).children('#left').css({'border':'2px solid red', 'border-right':'none'});
  $(this).children('#right').css({'border':'2px solid red'});
  }, 
  function () {
  $(this).children('#left').css({'border':'2px solid black', 'border-right':'none'});
  $(this).children('#right').css({'border':'2px solid black'});
 });
 });
 </script>

 </head>
 <body>

 <div id="wrapper">
 <div id="right">Some content here</div>
 <div id = "left"></div>
 </div>

 </body>
 </html>

You can use CSSPIE for rounded orners for IE

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难免孤独

2021-01-11 14:46

No. Divs are ALWAYS rectangular. You could fake it in a number of ways (using a background image would be one option).

As for using two DIVs, sure you could. The hover could be done with CSS3 and child selectors of a parent div or you could JavaScript to change the class of both divs when hovering over either one of them.

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时光说笑

2021-01-11 14:51

two options that I can think of:

1) give the div a background image and use CSS pseudo class :hover to change the background image to one that indicates a hover state

2) put three div's inside a wrapper, and position them so so you have one in the upper left hand corner, and then two stacked on top of each other, so that you can simulate the top half of a larger div missing the upper left half border. I don't think CSS alonw can target all the divs in order to change their borders, so will probably have to use JS to execute the hover behavior, by applying an event handler to all three divs.

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时光说笑

2021-01-11 14:53

Definitely requires two or three div's unless you use a background image

Here's a three-div solution

http://jsfiddle.net/pxfunc/SUuF6/

Its cross-browser compatible. The hover won't work in IE6, but it will in IE7+. The rounded corners will show based on browser support

HTML:

<div id="fancyShape">
    <div id="main">&lt;div&gt;</div>
    <div id="panHandle"></div>
</div>

CSS:

#fancyShape {position:relative;width:504px;height:304px;}

#main {
    margin-left:100px;
    width:400px;
    height:300px;
    border:solid 2px #000;
    border-radius:0 15px 15px 15px;

}
#panHandle {
    width:100px;
    height:120px;
    position:absolute;
    top:0;left:0;
    border-top:solid 2px #000;
    border-left:solid 2px #000;
    border-bottom:solid 2px #000;
    border-radius:15px 0 0 15px;
}

/* hover effect */
#fancyShape div {background-color:#fff;}
#fancyShape:hover div {background-color:#ff0;border-color:red;}

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