I know that I can use itertools.permutation to get all permutation of size r.
But, for itertools.permutation([1,2,3,4],3)
it will return (1,2,3)
as
It sounds like you are actually looking for itertools.combinations():
>>> from itertools import combinations
>>> list(combinations([1, 2, 3, 4], 3))
[(1, 2, 3), (1, 2, 4), (1, 3, 4), (2, 3, 4)]
This example also shows how to convert the result to a regular list, just pass it to the built-in list()
function.
To get the combinations for each length you can just use a loop like the following:
>>> data = [1, 2, 3, 4]
>>> for i in range(1, len(data)+1):
... print list(combinations(data, i))
...
[(1,), (2,), (3,), (4,)]
[(1, 2), (1, 3), (1, 4), (2, 3), (2, 4), (3, 4)]
[(1, 2, 3), (1, 2, 4), (1, 3, 4), (2, 3, 4)]
[(1, 2, 3, 4)]
Or to get the result as a nested list you can use a list comprehension:
>>> [list(combinations(data, i)) for i in range(1, len(data)+1)]
[[(1,), (2,), (3,), (4,)], [(1, 2), (1, 3), (1, 4), (2, 3), (2, 4), (3, 4)], [(1, 2, 3), (1, 2, 4), (1, 3, 4), (2, 3, 4)], [(1, 2, 3, 4)]]
For a flat list instead of nested:
>>> [c for i in range(1, len(data)+1) for c in combinations(data, i)]
[(1,), (2,), (3,), (4,), (1, 2), (1, 3), (1, 4), (2, 3), (2, 4), (3, 4), (1, 2, 3), (1, 2, 4), (1, 3, 4), (2, 3, 4), (1, 2, 3, 4)]
You need itertools.combinations()
. And to get a regular list, just use list()
factory function.
>>> from itertools import combinations
>>> list(combinations([1, 2, 3, 4], 3))
[(1, 2, 3), (1, 2, 4), (1, 3, 4), (2, 3, 4)]
Use itertools.combinations and a simple loop to get combinations of all size.
combinations
return an iterator so you've to pass it to list()
to see it's content(or consume it).
>>> from itertools import combinations
>>> lis = [1, 2, 3, 4]
for i in xrange(1, len(lis) + 1): # xrange will return the values 1,2,3,4 in this loop
print list(combinations(lis, i))
...
[(1,), (2,), (3,), (4,)]
[(1, 2), (1, 3), (1, 4), (2, 3), (2, 4), (3, 4)]
[(1, 2, 3), (1, 2, 4), (1, 3, 4), (2, 3, 4)]
[(1,2,3,4)]