Very illogical php value comparisons

前端 未结 8 2046
慢半拍i
慢半拍i 2021-01-11 12:58

I stumbled upon a very strange bit of PHP code. Could someone explain why this is happening? *****BONUS POINTS***** if you can tell my why this is useful.



        
相关标签:
8条回答
  • 2021-01-11 13:19

    I don't see how ('a'==0) is helpful

    $var = '123abc';
    
    if (123 == $var)
    {
        echo 'Whoda thunk it?';
    }
    

    It comes down to PHP's implicit conversion rules.

    I'm failing at thinking of a practical example, but that's the basic reason why you're seeing that behavior.

    Expansion:

    In your example, 'a' is converted to 0 (zero), for the comparison. Imagine that for the purpose of the comparison, it's equivalent to '0a'. (That's the numeral zero, not the letter 'o.')

    Further expansion:

    I thought there was a good example use case for this in the manual, but I failed to find it. What I did come across should help shed some light on this "illogical" situation.

    PHP is first and foremost a Web language, not a general-purpose scripting language. Since the Web is not typed and everything is a string, I had to do things slightly differently early on to make PHP do what people expected. Specifically, "123"==123 needs to be true in order to not have to type cast every single numeric user input.

    http://bugs.php.net/bug.php?id=48012

    That doesn't exactly answer the question, but it points in the general direction.

    0 讨论(0)
  • 2021-01-11 13:20

    Well, there's always the PHP type cheat sheet for that!

    0 讨论(0)
  • 2021-01-11 13:24

    Check out the PHP type comparison tables from the manual. It's a really handy thing to have close at hand until you've internalised it and has been invaluable to my understanding of exactly what will evaluate to true and when.

    Others have already answered the core of the question, but I think it's important to state that in PHP, the only non-empty string that does not evaluate to "true" with the == operator is "0" as PHP treats any string containing only numbers as an integer or float.

    The rationale for this is that PHP is fairly loosely typed and tries to allow integers, strings, floats and boolean values to be interchangeable. A real-world and extremely common example of this is if you're using the mysql or PDO functions, strings are returned for everything, even if the underlying column is an integer.

    Consider the following sql:

    CREATE TABLE `test`.`pants` (
    `id` INT NOT NULL AUTO_INCREMENT PRIMARY KEY ,
    `some_other_int` INT NOT NULL
    ) ENGINE = InnoDB;
    
    INSERT INTO `test`.`pants` (`id`, `some_other_int`)
    VALUES ('1', '1'), ('2', '0');
    

    And the following code:

    <?php
    
    $c = mysql_connect('127.0.0.1', 'user', 'password');
    mysql_select_db('test', $c);
    $r = mysql_query('SELECT * FROM pants', $c);
    
    while ($row = mysql_fetch_assoc($r)) {
        var_dump($row);
        foreach($row as $k=>$v) {
            if (!is_string($v))
                echo "field {$v} was not a string!\n";
        }
    }
    

    The "field x was not a string!" message is never printed, even though every column in the database is an integer. Suppose you want to actually use the second row in that table.

    <?php
    $id = 2;
    $r = mysql_query(sprintf('SELECT * FROM pants WHERE id=%s', mysql_real_esacpe_string($id)), $c);
    $row = mysql_fetch_assoc($r);
    
    // this is the important bit
    if (0 == $row['some_other_int']) {
        echo "It was zero!";
    }
    

    If the string "0" was not treated as the integer 0 for the comparison, the above code would never print "It was zero!". The programmer would be required to take responsibility for juggling the type of the value which comes out of the database. This is not desirable for a loosely typed language.

    Strict equality including type is tested using the "Is really, truly, honest to god equal to" operator, which is represented by the symbol "===".

    0 讨论(0)
  • 2021-01-11 13:27

    This is a basic principle of weakly/dynamically typed languages called type juggling. Types will be cast to other types in certain circumstances. When you compare a string to a number, the string will be cast into a number. When comparing anything to a boolean, that value will be cast to a boolean.

    There are rules for every type as to how it will be cast into another type or how it compares to other types. 'a' happens to be converted to 0 when cast to a number (the only logical choice, really). To avoid this type casting, test not with the equality operator ==, but with the identity operator ===.

    As James pointed out, this is useful since PHP deals a lot with strings that are really numbers. For example, HTML forms only submit strings, even if the value is a number. It also allows for some really terse code, like:

    $result = someOperation();
    if (!$result) {
        // $result may be null, false, 0, '' or array(),
        // all of which we're not interested in
        error();
    }
    

    It also means you have to be really careful about what to check for in which circumstances though, since a value might unexpectedly cast into something else. And admittedly, 'a' == 0 in itself is really a pitfall of type juggling rather than helpful. It's one of the situations where you have to be careful and test like if (is_numeric($var) && $var == 0).

    0 讨论(0)
  • 2021-01-11 13:32

    PHP is a loosely typed language, and allows you to compare values of different types without throwing errors, which makes it very easy to use but as you have found can cause some weird but logical outputs.

    Your first example:

    if(0=='a'){
        print ord(0)." should NEVER equal ".ord('a')."<br>";
    }
    

    When two different types of values are compared, one value is first turned into the same type as another via a cast and then compared. In the example of Int and String the string is converted into Int. When PHP turns a letter into a string it takes all the first numeric characters and then chops of the rest: i.e '123123afraa' becomes 123123, '9a9' becomes 9. If the string does not start with numerals it is given the value of 0.

    Therefor your example is really: 0===(string)'a' which is really 0===0 since 'a' does not start with a numeric. I think you were expecting PHP to return the value of 'a' in ASCII which it does not! This is really useful to sanitise strings, php rarely needs to deal with ascii values it is too high level for that. (Its for making websites!)

    When a string is compared to a boolean a value of '' or '0' are false, all other values are true. This is useful so you can check if a value is 'empty':

    url http://domain.com/?foo=

    if ($_GET['foo'])) { // do something }

    When an integer is compared to a boolean the values of 0 is false other values are true, this is pretty standard.

    So, all in all you need to understand what happens when different types of variables are compared with the == operator. Also it is probably wise to realise that == is almost never what you want and using === (which will not typecast your values) is ALOT safer.

    0 讨论(0)
  • 2021-01-11 13:36

    ord() takes characters, so PHP turns 0 into '0'. And 0 is equal to false, even though it is not identical (===).

    0 讨论(0)
提交回复
热议问题