How do I count the trailing zeros in integer?

Question

I am trying to write a function that returns the number of trailing 0s in a string or integer. Here is what I am trying and it is not returning the correct values.

Answer 1

Here are two examples of doing it:

1. Using rstrip and walrus := operator. Please notice that it only works in Python 3.8 and above.

   def end_zeros(num): return len(s := str(num)) - len(s.rstrip("0"))

2. Using re.findall() function:

   from re import findall

   def end_zeros(num): return len(findall("0*$", str(num))[0])

Answer 2

if you want to count how many zeros at the end of your int:

   def end_zeros(num):
        new_num = str(num)
        count = len(new_num) - len(new_num.rstrip("0"))
        return count



    print(end_zeros(0))  # == 1
    print(end_zeros(1))  # == 0
    print(end_zeros(10))  # == 1
    print(end_zeros(101))  # == 0
    print(end_zeros(245))  # == 0
    print(end_zeros(100100))  # == 2