I have a problem ,i solve it but i have written a long procedure and i can\'t be sure that it covers all the possible cases .
The problem:
If i have a
I found out probably the simplest solution.
.netFiddle
Compare gaps with "main interval".
//declare intervals
var secondryIntervals = new List<Tuple<DateTime, DateTime>> {
new Tuple<DateTime, DateTime>( new DateTime(2015, 03, 15, 4, 0, 0), new DateTime(2015, 03, 15, 5, 0, 0)),
new Tuple<DateTime, DateTime>( new DateTime(2015, 03, 15, 4, 10, 0), new DateTime(2015, 03, 15, 4, 40, 0)),
new Tuple<DateTime, DateTime>( new DateTime(2015, 03, 15, 4, 40, 0), new DateTime(2015, 03, 15, 5, 20, 0))};
var mainInterval = new Tuple<DateTime, DateTime>(new DateTime(2015, 03, 15, 3, 0, 0), new DateTime(2015, 03, 15, 7, 0, 0));
// add two empty intervals before and after main interval
secondryIntervals.Add(new Tuple<DateTime, DateTime>(mainInterval.Item1.AddMinutes(-1), mainInterval.Item1.AddMinutes(-1)));
secondryIntervals.Add(new Tuple<DateTime, DateTime>(mainInterval.Item2.AddMinutes(1), mainInterval.Item2.AddMinutes(1)));
secondryIntervals = secondryIntervals.OrderBy(s => s.Item1).ToList();
// endDate will rember 'biggest' end date
var endDate = secondryIntervals.First().Item1;
var result = secondryIntervals.Select(s =>
{
var temp = endDate;
endDate = endDate < s.Item2 ? s.Item2 : endDate;
if (s.Item1 > temp)
{
return new Tuple<DateTime, DateTime>(temp < mainInterval.Item1 ? mainInterval.Item1 : temp,
mainInterval.Item2 < s.Item1 ? mainInterval.Item2 : s.Item1);
}
return null;
})
// remove empty records
.Where(s => s != null && s.Item2 > s.Item1).ToList();
var minutes = result.Sum(s => (s.Item2 - s.Item1).TotalMinutes);
The algorithm requires O(n log n) time (for sorting) without additional storage and assumptions.
I had to solve this problem to digest some scheduling data. This allows multiple online times, but assumes that they do not overlap.
select convert(datetime,'1/1/2015 5:00 AM') StartDateTime, convert(datetime,'1/1/2015 5:00 PM') EndDateTime, convert(varchar(20),'Online') IntervalType into #CapacityIntervals
insert into #CapacityIntervals select '1/1/2015 4:00 AM' StartDateTime, '1/1/2015 6:00 AM' EndDateTime, 'Offline' IntervalType
insert into #CapacityIntervals select '1/1/2015 5:00 AM' StartDateTime, '1/1/2015 6:00 AM' EndDateTime, 'Offline' IntervalType
insert into #CapacityIntervals select '1/1/2015 10:00 AM' StartDateTime, '1/1/2015 12:00 PM' EndDateTime, 'Offline' IntervalType
insert into #CapacityIntervals select '1/1/2015 11:00 AM' StartDateTime, '1/1/2015 1:00 PM' EndDateTime, 'Offline' IntervalType
insert into #CapacityIntervals select '1/1/2015 4:00 PM' StartDateTime, '1/1/2015 6:00 PM' EndDateTime, 'Offline' IntervalType
insert into #CapacityIntervals select '1/1/2015 1:30 PM' StartDateTime, '1/1/2015 2:00 PM' EndDateTime, 'Offline' IntervalType
--Populate your Offline table
select
ROW_NUMBER() over (Order by StartDateTime, EndDateTime) Rownum,
StartDateTime,
EndDateTime
into #Offline
from #CapacityIntervals
where IntervalType in ('Offline','Cleanout')
group by StartDateTime, EndDateTime
--Populate your Online table
select
ROW_NUMBER() over (Order by StartDateTime, EndDateTime) Rownum,
StartDateTime,
EndDateTime
into #Online
from #CapacityIntervals
where IntervalType not in ('Offline','Cleanout')
--If you have overlapping online intervals... check for those here and consolidate.
-------------------------------
--find overlaping offline times
-------------------------------
declare @Finished as tinyint
set @Finished = 0
while @Finished = 0
Begin
update #Offline
set #Offline.EndDateTime = OverlapEndDates.EndDateTime
from #Offline
join
(
select #Offline.Rownum,
MAX(Overlap.EndDateTime) EndDateTime
from #Offline
join #Offline Overlap
on Overlap.StartDateTime between #Offline.StartDateTime and #Offline.EndDateTime
and #Offline.Rownum <= Overlap.Rownum
group by #Offline.Rownum
) OverlapEndDates
on #Offline.Rownum = OverlapEndDates.Rownum
--Remove Online times completely inside of online times
delete #Offline
from #Offline
join #Offline Overlap
on #Offline.StartDateTime between Overlap.StartDateTime and Overlap.EndDateTime
and #Offline.EndDateTime between Overlap.StartDateTime and Overlap.EndDateTime
and #Offline.Rownum > Overlap.Rownum
--LOOK IF THERE ARE ANY MORE CHAINS LEFT
IF NOT EXISTS(
select #Offline.Rownum,
MAX(Overlap.EndDateTime) EndDateTime
from #Offline
join #Offline Overlap
on Overlap.StartDateTime between #Offline.StartDateTime and #Offline.EndDateTime
and #Offline.Rownum < Overlap.Rownum
group by #Offline.Rownum
)
SET @Finished = 1
END
-------------------------------
--Modify Online times with offline ranges
-------------------------------
--delete any Online times completely inside offline range
delete #Online
from #Online
join #Offline
on #Online.StartDateTime between #Offline.StartDateTime and #Offline.EndDateTime
and #Online.EndDateTime between #Offline.StartDateTime and #Offline.EndDateTime
--Find Online Times with offline range at the beginning
update #Online
set #Online.StartDateTime = #Offline.EndDateTime
from #Online
join #Offline
on #Online.StartDateTime between #Offline.StartDateTime and #Offline.EndDateTime
and #Online.EndDateTime >= #Offline.EndDateTime
--Find Online Times with offline range at the end
update #Online
set #Online.EndDateTime = #Offline.StartDateTime
from #Online
join #Offline
on #Online.StartDateTime <= #Offline.StartDateTime
and #Online.EndDateTime between #Offline.StartDateTime and #Offline.EndDateTime
--Find Online Times with offline range punched in the middle
select #Online.Rownum,
#Offline.Rownum OfflineRow,
#Offline.StartDateTime,
#Offline.EndDateTime,
ROW_NUMBER() over (Partition by #Online.Rownum order by #Offline.Rownum Desc) OfflineHoleNumber
into #OfflineHoles
from #Online
join #Offline
on #Offline.StartDateTime between #Online.StartDateTime and #Online.EndDateTime
and #Offline.EndDateTime between #Online.StartDateTime and #Online.EndDateTime
declare @HoleNumber as integer
select @HoleNumber = isnull(MAX(OfflineHoleNumber),0) from #OfflineHoles
--Punch the holes out of the online times
While @HoleNumber > 0
Begin
insert into #Online
select
-1 Rownum,
#OfflineHoles.EndDateTime StartDateTime,
#Online.EndDateTime EndDateTime
from #Online
join #OfflineHoles
on #Online.Rownum = #OfflineHoles.Rownum
where OfflineHoleNumber = @HoleNumber
update #Online
set #Online.EndDateTime = #OfflineHoles.StartDateTime
from #Online
join #OfflineHoles
on #Online.Rownum = #OfflineHoles.Rownum
where OfflineHoleNumber = @HoleNumber
set @HoleNumber=@HoleNumber-1
end
--Output total hours
select SUM(datediff(second,StartDateTime, EndDateTime)) / 3600.0 TotalHr
from #Online
--see how it split up the online intervals
select *
from #Online
order by StartDateTime, EndDateTime
My solution is quite similar to Vladimir Baranov.
Link to .NetFiddle
General idea
My algorithm is based on a modification of interval tree. It assumes that smallest unit of time is 1 minute (easy to modify).
Each tree node is in 1 of 3 state: unvisited, visited and used. The algorithm is based on recursive Search function that can be described by following steps:
Solution in steps
Calculate sum of intervals.
Please note I assume that intervals are [start; end], i.e. both intervals are inclusive, what is easy to change.
Requirements
Assuming
n - number of "secondary intervals"
m - max time in base unit
Construction requires O(2n) storage space and work in O(n log n + m) time.
Here's my code
public class Interval
{
public int Start { get; set; }
public int End { get; set; }
};
enum Node
{
Unvisited = 0,
Visited = 1,
Used = 2
};
Node[] tree;
public void Calculate()
{
var secondryIntervalsAsDates = new List<Tuple<DateTime,DateTime>> { new Tuple<DateTime, DateTime>( new DateTime(2015, 03, 15, 4, 0, 0), new DateTime(2015, 03, 15, 5, 0, 0))};
var mainInvtervalAsDate = new Tuple<DateTime, DateTime>(new DateTime(2015, 03, 15, 3, 0, 0), new DateTime(2015, 03, 15, 7, 0, 0));
// calculate biggest interval
var startDate = secondryIntervalsAsDates.Union( new List<Tuple<DateTime,DateTime>>{mainInvtervalAsDate}).Min(s => s.Item1).AddMinutes(-1);
var endDate = secondryIntervalsAsDates.Union(new List<Tuple<DateTime, DateTime>> { mainInvtervalAsDate }).Max(s => s.Item2);
var mainInvterval = new Interval { Start = (int)(mainInvtervalAsDate.Item1 - startDate).TotalMinutes, End = (int)(mainInvtervalAsDate.Item2 - startDate).TotalMinutes };
var wholeInterval = new Interval { Start = 1, End = (int)(endDate - startDate).TotalMinutes};
//convert intervals to minutes
var secondaryIntervals = secondryIntervalsAsDates.Select(s => new Interval { Start = (int)(s.Item1 - startDate).TotalMinutes, End = (int)(s.Item2 - startDate).TotalMinutes}).ToList();
tree = new Node[wholeInterval.End * 2 + 1];
//insert secondary intervals
secondaryIntervals.ForEach(s => Search(wholeInterval, s, 1));
//insert main interval
var result = Search(wholeInterval, mainInvterval, 1);
//calculate result
var minutes = result.Sum(r => r.End - r.Start) + result.Count();
}
public IEnumerable<Interval> Search(Interval current, Interval searching, int index)
{
if (tree[index] == Node.Used || searching.End < searching.Start)
{
return new List<Interval>();
}
if (tree[index] == Node.Unvisited && current.Start == searching.Start && current.End == searching.End)
{
tree[index] = Node.Used;
return new List<Interval> { current };
}
tree[index] = Node.Visited;
return Search(new Interval { Start = current.Start, End = current.Start + (current.End - current.Start) / 2 },
new Interval { Start = searching.Start, End = Math.Min(searching.End, current.Start + (current.End - current.Start) / 2) }, index * 2).Union(
Search(new Interval { Start = current.Start + (current.End - current.Start) / 2 + 1 , End = current.End},
new Interval { Start = Math.Max(searching.Start, current.Start + (current.End - current.Start) / 2 + 1), End = searching.End }, index * 2 + 1));
}
Here is SQLFiddle with complete query.
I will show how I built a query that returns number of minutes for each emp_num, day_date
. If it turns out that no minutes are left for a particular emp_num, day_date
, then result would not have a row with 0
, there will be no such row at all.
General idea
I will use a table of numbers. We'll need only 24*60=1440
numbers, but it is a good idea to have such table in your database for other reports. I personally have it with 100,000 rows. Here is a very good article comparing different methods to generate such table.
For each interval I'm going to generate a set of rows using the table of numbers - one row for each minute in the interval. I assume that intervals are [start; end)
, i.e. start minute is inclusive, end minute is exclusive. For example, interval from 07:00
to 08:00
is 60
minutes, not 61
.
Generate a table of numbers
DECLARE @Numbers TABLE (N int);
INSERT INTO @Numbers(N)
SELECT TOP(24*60)
ROW_NUMBER() OVER(ORDER BY S.object_id) - 1 AS N
FROM
sys.all_objects AS S
ORDER BY N
;
For this task it is better to have numbers that start from 0. Normally you would have it as a permanent table with primary key on N
.
Sample data
DECLARE @Missions TABLE (emp_num int, day_date datetime, mission_in datetime, mission_out datetime);
DECLARE @Periods TABLE (emp_num int, day_date datetime, work_st datetime, work_end datetime, check_in datetime, check_out datetime, day_state char(1));
INSERT INTO @Missions (emp_num, day_date, mission_in, mission_out) VALUES
(547, '2015-04-01', '2015-04-01 15:00:00', '2015-04-01 21:30:00'),
(547, '2015-04-02', '2015-04-02 08:00:00', '2015-04-02 14:00:00');
INSERT INTO @Periods (emp_num, day_date, work_st, work_end, check_in, check_out, day_state) VALUES
(547, '2015-04-01', '2015-04-01 08:00:00', '2015-04-01 16:00:00', '2015-04-01 07:45:00', '2015-04-01 12:10:00', 'W'),
(547, '2015-04-01', '2015-04-01 08:00:00', '2015-04-01 16:00:00', '2015-04-01 12:45:00', '2015-04-01 17:24:00', 'W'),
(547, '2015-04-02', '2015-04-02 00:00:00', '2015-04-02 00:00:00', '2015-04-02 07:11:00', '2015-04-02 13:11:00', 'E');
My solution will not use the day_state
column. I expect that you would have 00:00:00
for both work_st
and work_end
. Solution expects that the date component within the same row is the same and that day_date
doesn't have time component.
If I designed the schema for this task I would have three tables instead of two: Missions
, WorkPeriods
and CheckPeriods
. I would split your table Periods
into two to avoid repeating work_st
and work_end
in several rows. But this solution would deal with your current schema and it will essentially generate this third table on the fly. In practice it means that performance may be improved.
Mission minutes
WITH
CTE_MissionMinutes
AS
(
SELECT emp_num, day_date, N.N
FROM
@Missions AS M
CROSS JOIN @Numbers AS N
WHERE
N.N >= DATEDIFF(minute, M.day_date, M.mission_in) AND
N.N < DATEDIFF(minute, M.day_date, M.mission_out)
)
Each original row from @Missions
turns into a set of rows, one for each minute of the interval (mission_in, mission_out)
.
Work periods
,CTE_WorkPeriods
AS
(
SELECT P.emp_num, P.day_date, P.work_st, P.work_end
FROM @Periods AS P
GROUP BY P.emp_num, P.day_date, P.work_st, P.work_end
)
Generate a third helper table - one row for each emp_num, day_date, work_st, work_end
- all intervals for (work_st, work_end)
.
Work and Check minutes
,CTE_WorkMinutes
AS
(
SELECT emp_num, day_date, N.N
FROM
CTE_WorkPeriods
CROSS JOIN @Numbers AS N
WHERE
N.N >= DATEDIFF(minute, CTE_WorkPeriods.day_date, CTE_WorkPeriods.work_st) AND
N.N < DATEDIFF(minute, CTE_WorkPeriods.day_date, CTE_WorkPeriods.work_end)
)
,CTE_CheckMinutes
AS
(
SELECT emp_num, day_date, N.N
FROM
@Periods AS P
CROSS JOIN @Numbers AS N
WHERE
N.N >= DATEDIFF(minute, P.day_date, P.check_in) AND
N.N < DATEDIFF(minute, P.day_date, P.check_out)
)
Exactly the same as for Missions
.
Union "secondary intervals"
,CTE_UnionPeriodMinutes
AS
(
SELECT emp_num, day_date, N
FROM CTE_WorkMinutes
UNION ALL -- can be not ALL here, but ALL is usually faster
SELECT emp_num, day_date, N
FROM CTE_CheckMinutes
)
Subtract secondary intervals from primary
,CTE_FinalMinutes
AS
(
SELECT emp_num, day_date, N
FROM CTE_MissionMinutes
EXCEPT
SELECT emp_num, day_date, N
FROM CTE_UnionPeriodMinutes
)
Sum up number of minutes
SELECT
emp_num
,day_date
,COUNT(*) AS FinalMinutes
FROM CTE_FinalMinutes
GROUP BY emp_num, day_date
ORDER BY emp_num, day_date;
To make the final query just put all CTEs together.
Result set
emp_num day_date FinalMinutes
547 2015-04-01 00:00:00.000 246
547 2015-04-02 00:00:00.000 49
There are 246 minutes between 17:24 and 21:30.
There are 49 minutes between 13:11 and 14:00.
Here is SQLFiddle with complete query.
It is fairly easy to show actual intervals that lead to this SUM
of minutes, but you said you need just the SUM
.
I've updated my answer with your data example and I'm adding another example for an employee 248 that uses case 2 and 5 from your graph.
--load example data for emply 547
select CONVERT(int, 547) emp_num,
Convert(datetime, '2015-4-1') day_date,
Convert(datetime, '2015-4-1 08:00') work_st,
Convert(datetime, '2015-4-1 16:00') work_end,
Convert(datetime, '2015-4-1 07:45') check_in,
Convert(datetime, '2015-4-1 12:10') check_out,
'W' day_state
into #SecondaryIntervals
insert into #SecondaryIntervals select 547, '2015-4-1', '2015-4-1 08:00', '2015-4-1 16:00', '2015-4-1 12:45', '2015-4-1 17:24', 'W'
insert into #SecondaryIntervals select 547, '2015-4-2', '2015-4-2 00:00', '2015-4-2 00:00', '2015-4-2 07:11', '2015-4-2 13:11', 'E'
select CONVERT(int, 547) emp_num,
Convert(datetime, '2015-4-1') day_date,
Convert(datetime, '2015-4-1 15:00') mission_in,
Convert(datetime, '2015-4-1 21:30') mission_out
into #MainIntervals
insert into #MainIntervals select 547, '2015-4-2', '2015-4-2 8:00', '2015-4-2 14:00'
--load more example data for an employee 548 with overlapping secondary intervals
insert into #SecondaryIntervals select 548, '2015-4-1', '2015-4-1 06:00', '2015-4-1 11:00', '2015-4-1 9:00', '2015-4-1 10:00', 'W'
insert into #SecondaryIntervals select 548, '2015-4-1', '2015-4-1 06:00', '2015-4-1 11:00', '2015-4-1 10:30', '2015-4-1 12:30', 'W'
insert into #SecondaryIntervals select 548, '2015-4-1', '2015-4-1 06:00', '2015-4-1 11:00', '2015-4-1 13:15', '2015-4-1 16:00', 'W'
insert into #MainIntervals select 548, '2015-4-1', '2015-4-1 8:00', '2015-4-1 14:00'
--Populate your Offline table with the intervals in #SecondaryIntervals
select
ROW_NUMBER() over (Order by emp_num, day_date, StartDateTime, EndDateTime) Rownum,
emp_num,
day_date,
StartDateTime,
EndDateTime
into #Offline
from
(select emp_num,
day_date,
work_st StartDateTime,
work_end EndDateTime
from #SecondaryIntervals
where day_state = 'W'
Group by emp_num,
day_date,
work_st,
work_end
union
select
emp_num,
day_date,
check_in StartDateTime,
check_out EndDateTime
from #SecondaryIntervals
Group by emp_num,
day_date,
check_in,
check_out
) SecondaryIntervals
--Populate your Online table
select
ROW_NUMBER() over (Order by emp_num, day_date, mission_in, mission_out) Rownum,
emp_num,
day_date,
mission_in StartDateTime,
mission_out EndDateTime
into #Online
from #MainIntervals
group by emp_num,
day_date,
mission_in,
mission_out
-------------------------------
--find overlaping offline times
-------------------------------
declare @Finished as tinyint
set @Finished = 0
while @Finished = 0
Begin
update #Offline
set #Offline.EndDateTime = OverlapEndDates.EndDateTime
from #Offline
join
(
select #Offline.Rownum,
MAX(Overlap.EndDateTime) EndDateTime
from #Offline
join #Offline Overlap
on #Offline.emp_num = Overlap.emp_num
and #Offline.day_date = Overlap.day_date
and Overlap.StartDateTime between #Offline.StartDateTime and #Offline.EndDateTime
and #Offline.Rownum <= Overlap.Rownum
group by #Offline.Rownum
) OverlapEndDates
on #Offline.Rownum = OverlapEndDates.Rownum
--Remove Online times completely inside of online times
delete #Offline
from #Offline
join #Offline Overlap
on #Offline.emp_num = Overlap.emp_num
and #Offline.day_date = Overlap.day_date
and #Offline.StartDateTime between Overlap.StartDateTime and Overlap.EndDateTime
and #Offline.EndDateTime between Overlap.StartDateTime and Overlap.EndDateTime
and #Offline.Rownum > Overlap.Rownum
--LOOK IF THERE ARE ANY MORE CHAINS LEFT
IF NOT EXISTS(
select #Offline.Rownum,
MAX(Overlap.EndDateTime) EndDateTime
from #Offline
join #Offline Overlap
on #Offline.emp_num = Overlap.emp_num
and #Offline.day_date = Overlap.day_date
and Overlap.StartDateTime between #Offline.StartDateTime and #Offline.EndDateTime
and #Offline.Rownum < Overlap.Rownum
group by #Offline.Rownum
)
SET @Finished = 1
END
-------------------------------
--Modify Online times with offline ranges
-------------------------------
--delete any Online times completely inside offline range
delete #Online
from #Online
join #Offline
on #Online.emp_num = #Offline.emp_num
and #Online.day_date = #Offline.day_date
and #Online.StartDateTime between #Offline.StartDateTime and #Offline.EndDateTime
and #Online.EndDateTime between #Offline.StartDateTime and #Offline.EndDateTime
--Find Online Times with offline range at the beginning
update #Online
set #Online.StartDateTime = #Offline.EndDateTime
from #Online
join #Offline
on #Online.emp_num = #Offline.emp_num
and #Online.day_date = #Offline.day_date
and #Online.StartDateTime between #Offline.StartDateTime and #Offline.EndDateTime
and #Online.EndDateTime >= #Offline.EndDateTime
--Find Online Times with offline range at the end
update #Online
set #Online.EndDateTime = #Offline.StartDateTime
from #Online
join #Offline
on #Online.emp_num = #Offline.emp_num
and #Online.day_date = #Offline.day_date
and #Online.StartDateTime <= #Offline.StartDateTime
and #Online.EndDateTime between #Offline.StartDateTime and #Offline.EndDateTime
--Find Online Times with offline range punched in the middle
select #Online.Rownum,
#Offline.Rownum OfflineRow,
#Offline.StartDateTime,
#Offline.EndDateTime,
ROW_NUMBER() over (Partition by #Online.Rownum order by #Offline.Rownum Desc) OfflineHoleNumber
into #OfflineHoles
from #Online
join #Offline
on #Online.emp_num = #Offline.emp_num
and #Online.day_date = #Offline.day_date
and #Offline.StartDateTime between #Online.StartDateTime and #Online.EndDateTime
and #Offline.EndDateTime between #Online.StartDateTime and #Online.EndDateTime
declare @HoleNumber as integer
select @HoleNumber = isnull(MAX(OfflineHoleNumber),0) from #OfflineHoles
--Punch the holes out of the online times
While @HoleNumber > 0
Begin
insert into #Online
select
-1 Rownum,
#Online.emp_num,
#Online.day_date,
#OfflineHoles.EndDateTime StartDateTime,
#Online.EndDateTime EndDateTime
from #Online
join #OfflineHoles
on #Online.Rownum = #OfflineHoles.Rownum
where OfflineHoleNumber = @HoleNumber
update #Online
set #Online.EndDateTime = #OfflineHoles.StartDateTime
from #Online
join #OfflineHoles
on #Online.Rownum = #OfflineHoles.Rownum
where OfflineHoleNumber = @HoleNumber
set @HoleNumber=@HoleNumber-1
end
--Output total hours
select emp_num, day_date,
SUM(datediff(second,StartDateTime, EndDateTime)) / 3600.0 TotalHr,
SUM(datediff(second,StartDateTime, EndDateTime)) / 60.0 TotalMin
from #Online
group by emp_num, day_date
order by 1, 2
--see how it split up the online intervals
select emp_num, day_date, StartDateTime, EndDateTime
from #Online
order by 1, 2, 3, 4
Output is:
emp_num day_date TotalHr TotalMin
----------- ----------------------- --------------------------------------- ---------------------------------------
547 2015-04-01 00:00:00.000 4.100000 246.000000
547 2015-04-02 00:00:00.000 0.816666 49.000000
548 2015-04-01 00:00:00.000 0.750000 45.000000
(3 row(s) affected)
emp_num day_date StartDateTime EndDateTime
----------- ----------------------- ----------------------- -----------------------
547 2015-04-01 00:00:00.000 2015-04-01 17:24:00.000 2015-04-01 21:30:00.000
547 2015-04-02 00:00:00.000 2015-04-02 13:11:00.000 2015-04-02 14:00:00.000
548 2015-04-01 00:00:00.000 2015-04-01 12:30:00.000 2015-04-01 13:15:00.000
(3 row(s) affected)
I left my other answer posted because it's more generic in case someone else wants to snag it. I see you added a bounty to this question. Let me know if there's something specific about my answer that doesn't satisfy you and I'll try to help you out. I process thousands of intervals with this method and it returns in just a few seconds.