What does the “More Columns than Column Names” error mean?

Question

I\'m trying to read in a .csv file from the IRS and it doesn\'t appear to be formatted in any weird way.

I\'m using the read.table() function, which I h

Answer 1

Depending on the data (e.g. tsv extension) it may use tab as separators, so you may try sep = '\t' with read.csv.

Answer 2

For the Germans:

you have to change your decimal commas into a Full stop in your csv-file (in Excel:File -> Options -> Advanced -> "Decimal seperator") , then the error is solved.

Answer 3

you have have strange characters in your heading # % -- or ,

Answer 4

This error can get thrown if your data frame has sf geometry columns.

Answer 5

It uses commas as separators. So you can either set sep="," or just use read.csv:

x <- read.csv(file="http://www.irs.gov/file_source/pub/irs-soi/countyinflow1011.csv")
dim(x)
## [1] 113593      9

The error is caused by spaces in some of the values, and unmatched quotes. There are no spaces in the header, so read.table thinks that there is one column. Then it thinks it sees multiple columns in some of the rows. For example, the first two lines (header and first row):

State_Code_Dest,County_Code_Dest,State_Code_Origin,County_Code_Origin,State_Abbrv,County_Name,Return_Num,Exmpt_Num,Aggr_AGI
00,000,96,000,US,Total Mig - US & For,6973489,12948316,303495582

And unmatched quotes, for example on line 1336 (row 1335) which will confuse read.table with the default quote argument (but not read.csv):

01,089,24,033,MD,Prince George's County,13,30,1040