How can I create a slice object for Numpy array?

Question

I\'ve tried to find a neat solution to this, but I\'m slicing several 2D arrays of the same shape in the same manner. I\'ve tidied it up as much as I can by defining a list

Answer 1

You can index a multidimensional array by using a tuple of slice objects.

window = slice(col_start, col_stop), slice(row_start, row_stop)
a1 = array1[window]
a2 = array2[window] 

This is not specific to numpy and is simply how subscription/slicing syntax works in python.

class mock_array:
    def __getitem__(self, key):
        print(key)
m = mock_array()
m[1:3, 7:9] # prints tuple(slice(1, 3, None), slice(7, 9, None))

Answer 2

Yes you can use numpy.s_:

Example:

>>> a = np.arange(10).reshape(2, 5)
>>> 
>>> m = np.s_[0:2, 3:4]
>>> 
>>> a[m]
array([[3],
       [8]])

And in this case:

my_slice = np.s_[cpix[1]-50:cpix[1]+50, cpix[0]-50:cpix[0]+50]

a1 = array1[my_slice] 
a2 = array2[my_slice] 
a3 = array3[my_slice]

You can also use numpy.r_ in order to translates slice objects to concatenation along the first axis.