Why will std::rel_ops::operators be deprecated in C++20?

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心在旅途
心在旅途 2021-01-07 18:19

According to cppreference.com, std::rel_ops::operator!=,>,<=,>= will be deprecated in C++20.

What\'s the rationale behind?

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  • 2021-01-07 18:29

    What's the rationale behind?

    rel_ops was deprecated by Library Support for the Spaceship (Comparison) Operator. The paper doesn't list any motivation, but it does appear in the spaceship paper:

    This subsumes namespace std::rel_ops, so we propose also removing (or deprecating) std::rel_ops.

    There are four reasons mentioned in the paper (including correctness and performance). But one big one not mentioned in either paper is that std::rel_ops just... doesn't work. Rule of thumb is that operators are found using ADL. rel_ops doesn't give you ADL-findable operators, it just declares unconstrained function templates like:

    namespace std {
        namespace rel_ops {
            template< class T >
            bool operator!=( const T& lhs, const T& rhs ) 
            {
                return !(lhs == rhs);
            }
        }    
    }
    

    So using algorithms like:

    struct X { ... };
    bool operator<(X const&, X const&) { ... };
    std::sort(values.begin(), values.end(), std::greater<>{});
    

    Just doesn't work, unless you make sure to:

    #include <utility>
    using namespace std::rel_ops;
    

    Fairly consistently everywhere as your first include to ensure that these operators are visible at the point of definition of every function template you could possibly call.

    So operator<=> is just strictly superior:

    • It actually works.
    • You only have to write one function (<=>) instead of two (== and <)
    • Typically, you actually have to write zero functions (= default)
    • Did I mention it actually works?
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  • 2021-01-07 18:39

    C++20 provides Three way comparison thus the unique ones will become deprecated.

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  • 2021-01-07 18:47

    In C++20, you get three-way comparison (operator <=>), which automatically "generates" default comparisons if provided:

    struct A {
       // You only need to implement a single operator.
       std::strong_ordering operator<=>(const A&) const;
    };
    
    // Compiler generates 4 relational operators (you need to default the
    // three-way comparison operator to get == and !=).
    A to1, to2;
    if (to1 > to2) { /* ... */ } // ok
    if (to1 <= to2) { /* ... */ } // ok, single call to <=>
    

    There are multiple advantages of the three-way comparison over std::rel_ops, which is probably why std::rel_ops operators are deprecated. On top of my head:

    • It is more versatile, since, depending on the return type of operator<=> (std::strong_ordering, std::weak_ordering, ...), only relevant operators are generated. See the <compare> header for more information.

    • You do not bring a bunch of templated operator overloads by doing using namespace std::rel_ops.

    • You can ask the compiler to generate the three-way operator for you by defaulting it (auto operator<=>(A const&) = default) — This will basically generate a lexicographic comparison of base classes and non-static data members, plus it will deduce the right type of ordering if the return type is auto.

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