JS cookie for displaying content after x-th pageview

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日久生厌
日久生厌 2021-01-07 16:00

I am trying to find how may I set a javascript cookie so it displays a fancybox popup after say 4-th pageview of visitor.

Here is the code that I am using to display

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  • 2021-01-07 16:29

    Update April 02, 2019

    As mentioned in the comments by @Gregdebrick the answer is being update to use the JavaScript Cookie plugin https://github.com/js-cookie/js-cookie instead of the deprecated jQuery Cookie plugin.

    So, after loading the JS Cookie plugin from CDN in your page:

    <script src="https://cdn.jsdelivr.net/npm/js-cookie@2/src/js.cookie.min.js"></script>
    

    Use the following script:

    $(document).ready(function () {
        // if the cookie is undefined, create it
        if(typeof Cookies.get('visited') === "undefined"){
            Cookies.set("visited", 0);
        }
        // Cookies.get('visited') returns a string
        if (parseInt(Cookies.get('visited')) >= 3) {
            // open fancybox after 3 secs on 4th visit
            setTimeout(function () {
                $.fancybox.open({
                    // your fancybox API options here
                });
            }, 3000);
        } else {
            let increase = parseInt(Cookies.get('visited')) + 1;
            Cookies.set('visited', increase, { expires: 1 });
            return false;
        }
    }); // ready
    

    See updated working DEMO


    Assuming that you are using the jQuery Cookie Plugin, then you could use the following code to launch fancybox after 3 seconds, the 4th page visit on the same day :

    $(document).ready(function () {
        // create cookie
        var visited = $.cookie('visited'); // visited = 0
        if (visited >= 3) {
            // open fancybox after 3 secs on 4th visit or further on the same day
            setTimeout(function () {
                $.fancybox.open({
                    // your fancybox API options here
                });
            }, 3000);
        } else {
            visited++; // increase counter of visits
            // set new cookie value to match visits
            $.cookie('visited', visited, {
                expires: 1 // expires after one day
            });
            return false;
        }
    }); // ready
    

    See working DEMO

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