Unreported exception java.lang.exception

Question

Unreported exception java.lang.exception : Must be caught or declared to be throw. Why this problem will occur? Is it some simple method that can help to solve this problems

Answer 1

Your encrypt() method throws an Exception. This means that where you're calling this method, you should explictly throw this Exception or handle it using a try-catch block.

In your case, for this particular code:

byte[] pass = encrypt(password);
String pw = new String(pass);

You should either enclose it in:

try{
 byte[] pass = encrypt(password);
 String pw = new String(pass);
}catch(Exception exe){
 //Your error handling code
}

or declare the method where this code is enclosed with throws Exception.

• If you are new to exception handling, consider reading this: Lesson: Exceptions from the Java Tutorials

• Also, here's another interesting read on "Guidelines on Exception propagation (in Java)"

Answer 2

1. There are 2 ways to handle the exception.

 - Either `declare` it
 - or `Handle` it.

2. encrypt() method above throws an Exception

So either declare it on the method declaration in which you are calling it.

eg:

public void MyCallingMethod() throws Exception{

     byte[] pass = encrypt(password);
     String pw = new String(pass);


}

Or handle it with try/catch block, finally is optional

try{

     byte[] pass = encrypt(password);
     String pw = new String(pass);
   }catch(Exception ex){


  }