how to make Designable UIImage in Swift

Question

I am a beginner. I want to make a swift file that contains a code to make Designable UIImage, so I will not edit the UI element display by coding, just in Interface builder

Answer 1

You can't use UIImage as designable because UIImage is not a UIView subclass you need to make designable your UIImageView instead, the UIImage can't be rendered by itself needs a UIImageView to be rendered

Use this class

import UIKit

@IBDesignable
class RoundableImageView: UIImageView {

    @IBInspectable var cornerRadius : CGFloat = 0.0{
        didSet{
            self.applyCornerRadius()
        }
    }

    @IBInspectable var borderColor : UIColor = UIColor.clear{
        didSet{
            self.applyCornerRadius()
        }
    }

    @IBInspectable var borderWidth : Double = 0{
        didSet{
            self.applyCornerRadius()
        }
    }

    @IBInspectable var circular : Bool = false{
        didSet{
            self.applyCornerRadius()
        }
    }

    func applyCornerRadius()
    {
        if(self.circular) {
            self.layer.cornerRadius = self.bounds.size.height/2
            self.layer.masksToBounds = true
            self.layer.borderColor = self.borderColor.cgColor
            self.layer.borderWidth = CGFloat(self.borderWidth)
        }else {
            self.layer.cornerRadius = cornerRadius
            self.layer.masksToBounds = true
            self.layer.borderColor = self.borderColor.cgColor
            self.layer.borderWidth = CGFloat(self.borderWidth)
        }
    }

    override func awakeFromNib() {
        super.awakeFromNib()
        self.applyCornerRadius()
    }

    override func layoutSubviews() {
        super.layoutSubviews()
        applyCornerRadius()
    }

}