Creating dictionary of dictionaries in python 2.6

Question

I have a line of code in python2.7 that generates a dictionary of empty dictionaries:

values=[0,1,2,4,5,8] 
value_dicts={x:{} for x in values}

Answer 1

You can use the dict() constructor:

value_dicts = dict((x, {}) for x in values)

This uses a generator expression that constructs (key, value) tuples, which the dict() constructor is happy to turn into a dictionary for you.

Demo:

>>> values=[0,1,2,4,5,8] 
>>> dict((x, {}) for x in values)
{0: {}, 1: {}, 2: {}, 4: {}, 5: {}, 8: {}}

The syntax you used (a dict comprehension) was not introduced until Python 2.7 and Python 3, see PEP 274.

Answer 2

Depending on your intended use, you could also just use a defaultdict instead.

from collections import defaultdict
value_dicts = defaultdict(lambda: defaultdict(int))