Haskell foldl signature is in unexpected notation

前端 未结 0 719
-上瘾入骨i
-上瘾入骨i 2021-01-07 08:13

I have checked signature of foldl function and this is the result:

> :t foldl
foldl :: Foldable t => (b -> a -> b) -> b -> t a          


        
相关标签:
回答
  • 消灭零回复
提交回复
热议问题