why and how does rand() exist both in global and std namespace in cstdlib?

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灰色年华
灰色年华 2021-01-07 07:53

I understand that rand(), as an example function from , exists both in the global and the std namespace.

In ef

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  • 2021-01-07 08:31

    The reason is that it's originally a C function. It comes from C.

    C++ re-implemented C functions like these into a std namespace. There is no difference that I know of, but it is recommended that C++ programmers use the function in the std:: namespace, first including the "c"whatever header (which is what you have indeed done with the "cstdlib" header).

    (Plain C programmers would include the "stdlib.h" header, by the way.)

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  • 2021-01-07 08:40

    The behavior is Uspecified behavior as per standard.
    As per the standard including cstdlib imports the symbol names in std namespace and possibly in Global namespace. If you rely on symbol names being included in global namespace then your program is non portable and you are relying on behavior of a specific implementation.


    To not rely on the implementatio behavior you must:

    Include cstdlib and use fully qualified name for rand.

    std::rand()
    

    References:

    C++11 Standard: D.5 C standard library headers
    Para 3:

    [ Example: The header <cstdlib> assuredly provides its declarations and definitions within the namespace std. It may also provide these names within the global namespace. The header <stdlib.h> assuredly provides the same declarations and definitions within the global namespace, much as in the C Standard. It may also provide these names within the namespace std. —end example ]


    Good Read:
    Should I include <xxxx.h> or <cxxxx> in C++ programs?

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