SQL command to sum by day/month

Question

I have the following table:

+----+---------------------+-------------+-----------------+
| id | stat_time           |       reads |          writes |
+----+-         


        

Answer 1

You want to convert the stat_time to a day to do this. The method depends on the database. Here is one way:

SELECT cast(stat_time as date) as stat_day, SUM(reads), SUM(writes)
from this_table
GROUP BY cast(stat_time as date)
order by stat_day;

Here are some other approaches (for MySQL and Oracle):

SELECT date(stat_time) as stat_day, SUM(reads), SUM(writes)
from this_table
GROUP BY date(stat_time)
order by stat_day;

SELECT trunc(stat_time) as stat_day, SUM(reads), SUM(writes)
from this_table
GROUP BY trunc(stat_time)
order by stat_day;

Answer 2

let's assume you have a column with name D-DATE_START so

$query = 'SELECT cast(D_DATE_START as date) as stat_day ,'
        .'sum(I_REV_MODEL) as totalDayRevenu '
        .'FROM t_show WHERE FK_MODEL=136 '
        ."and t_show.D_DATE_START between '".$after."' and '".$before."'"
        .' GROUP BY cast(D_DATE_START as date) '
        .' ORDER BY stat_day ';