How do I call a method that is a hash value?

Question

Previously, I asked about a clever way to execute a method on a given condition \"Ruby a clever way to execute a function on a condition.\"

The solutions and respons

Answer 1

table = {
  :a => 'test',
  :b => 12,
  :c => lambda { "Hallo" },
  :d => def print(); "Hallo in test"; end
}

puts table[:a]
puts table[:b]
puts table[:c].call
puts table[:d].send( :print )

Answer 2

that code doesn't work. it executes a at the time it is added to the hash, not when it is retrieved from the hash (try it in irb).

It doesn't work in the class because there is no a method defined on the class (you eventually define a method a on the instance.

Try actually using lambdas like

{0 => lambda { puts "hello world" }} 

instead

Answer 3

I am pretty new to using callbacks in Ruby and this is how I explained it to myself using an example:

require 'logger'
log = Logger.new('/var/tmp/log.out')

def callit(severity, msg, myproc)
  myproc.call(sev, msg)
end

lookup_severity = {}
lookup_severity['info'] = Proc.new { |x| log.info(x) }
lookup_severity['debug'] = Proc.new { |x| log.debug(x) }

logit = Proc.new { |x,y| lookup_sev[x].call(y) }

callit('info', "check4", logit)
callit('debug', "check5", logit)

Answer 4

If you really just want to pretty this sort of thing up, why not wrap all your methods in a class like so:

# a container to store all your methods you want to use a hash to access
class MethodHash
  alias [] send
  def one
    puts "I'm one"
  end
  def two
    puts "I'm two"
  end
end

x = MethodHash.new
x[:one] # prints "I'm one"
x.two # prints "I'm one"

or, to use your example:

# a general purpose object that transforms a hash into calls on methods of some given object
class DelegateHash
  def initialize(target, method_hash)
    @target = target
    @method_hash = method_hash.dup
  end
  def [](k)
    @target.send(@method_hash[k])
  end
end

class A
  def initialize
    @a = DelegateHash.new(self, { 0 => :a })
  end
  def a()
    puts "hello world"
  end
  def b()
    @a[0]
  end
end

x = A.new
x.a #=> prints "hello world"
x.b #=> prints "hello world"

One other basic error that you made is that you initialized @a outside of any instance method - just bare inside of the definition of A. This is a big time no-no, because it just doesn't work. Remember, in ruby, everything is an object, including classes, and the @ prefix means the instance variable of whatever object is currently self. Inside an instance method definitions, self is an instance of the class. But outside of that, just inside the class definition, self is the class object - so you defined an instance variable named @a for the class object A, which none of the instances of A can get to directly.

Ruby does have a reason for this behaviour (class instance variables can be really handy if you know what you're doing), but this is a more advanced technique.

In short, only initialize instance variables in the initialize method.

Answer 5

First of all, you are not putting a lambda in the hash. You're putting the result of calling a() in the current context.

Given this information, consider what the code in your class means. The context of a class definition is the class. So you define an instance method called a, and assign a class instance variable to the a hash containing the result of calling a in the current context. The current context is the class A, and class A does not have a class method called a, so you're trying to put the result of a nonexistent method there. Then in the instance method b, you try to access an instance variable called @a -- but there isn't one. The @a defined in the class context belongs to the class itself, not any particular instance.

So first of all, if you want a lambda, you need to make a lambda. Second, you need to be clear about the difference between a class and an instance of that class.

If you want to make a list of method names to be called on certain conditions, you can do it like this:

class A
  def self.conditions() { 0 => :a } end

  def a
    puts "Hello!"
  end

  def b(arg)
    send self.class.conditions[arg]
  end
end

This defines the conditions hash as a method of the class (making it easy to access), and the hash merely contains the name of the method to call rather than a lambda or anything like that. So when you call b(0), it sends itself the message contained in A.conditions[0], which is a.

Answer 6

a = ->(string="No string passed") do

puts string

end

some_hash = { 0 => a }

some_hash[0].call("Hello World")

some_hash[0][]