I have data that looks like this:
address | id
12AnyStreet | 1234
12AnyStreet | 1235
12AnyStreet | 1236
12AnyStreet | 1237
You can transform this data using the PIVOT function in SQL Server. In order to PIVOT
the data, you will want to create your new column using the row_number()
.
If you have a known number of values, then you can hard-code the query:
select *
from
(
select address, id,
'id_'+cast(row_number() over(partition by address
order by id) as varchar(20)) rn
from yourtable
) src
pivot
(
max(id)
for rn in ([id_1], [id_2], [id_3], [id_4])
) piv
See SQL Fiddle with Demo
But if the values are unknown then you will need to use dynamic SQL:
DECLARE @cols AS NVARCHAR(MAX),
@query AS NVARCHAR(MAX)
select @cols = STUFF((SELECT distinct ','
+ QUOTENAME(rn)
from
(
select 'id_'+cast(row_number() over(partition by address
order by id) as varchar(20)) rn
from yourtable
) src
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set @query = 'SELECT address,' + @cols + ' from
(
select address, id,
''id_''+cast(row_number() over(partition by address
order by id) as varchar(20)) rn
from yourtable
) x
pivot
(
max(id)
for rn in (' + @cols + ')
) p '
execute(@query)
See SQL Fiddle with Demo
The result of both queries is:
| ADDRESS | ID_1 | ID_2 | ID_3 | ID_4 |
-------------------------------------------
| 12AnyStreet | 1234 | 1235 | 1236 | 1237 |