BeautifulSoup HTML getting src link

Question

I\'m making a small web crawler using python 3.5.1 and requests module, which downloads all comics from a specific website.I\'m experimenting with one page. I parse the page

Answer 1

I would do it in one go using a CSS selector:

for img in soup.select("a.img-link img[src]"):
    print(img["src"])

Here, we are getting all of the img elements having an src attribute located under an a element with a img-link class. It prints:

http://2.p.mpcdn.net/352582/687224/1.jpg
http://2.p.mpcdn.net/352582/687224/2.jpg
http://2.p.mpcdn.net/352582/687224/3.jpg
http://2.p.mpcdn.net/352582/687224/4.jpg
...
http://2.p.mpcdn.net/352582/687224/20.jpg

---

If you still want to use the find_all(), you would have to nest it:

for link in soup.find_all("a", class_ = "img-link"):
    for img in link.find_all("a", src=True):  # searching for img with src attribute
        print(img["src"])