The other day, I gave an answer to this question but then other user solved that problem with sum + case conditional statement to add one edge condition in result. So, the q
Lets try to split the problem in 2 parts.
First, let suppose you want a field saying if the jobname is 'Analyst' or not.
SELECT
deptno,
CASE WHEN jobname = 'Analyst' THEN 1 ELSE 0 END AS IsAnalyst
FROM
employees
This query is going to return 0 for all the jobname that are no 'Analyst' and 1 for all the ones that are 'Analyst'
At this point you will have something like this
deptno IsAnalyst
1 1
1 0
1 0
2 0
2 1
2 1
2 1
2 0
Second, You want to summarize this information by department
SELECT
deptno,
SUM(CASE WHEN jobname = 'Analyst' THEN 1 ELSE 0 END) AS numAnalysts
FROM
employees
GROUP BY
deptno
You are applying a sum to all those value and grouping by deptno.
At this point (I removed the order by
from the query to simplify it) you will have the following output
deptno numAnalysts
1 1
2 3
I think that an example is worth a thousand words
Hope this helps
Presumably, this is the part that you are struggling to understand:
select deptno,
sum(case when jobname = 'Analyst' then 1 else 0 end) as numAnalysts
from employees
group by deptno
This is a simple aggregation query, really. What the query is doing is:
employees
jobname
is 'Analyst'
then assign the value of 1
(this is the case
statement. Otherwise, assign a value of
0`.case
is an expression that returns a value. The sum()
is simply adding up that value for each group.