Doctrine2 Mongodb adding more $or operator

Question

It is possible for doctrine2 ODM to create the following query?

db.Product.find({ \"$or\": [ { \"name\": new RegExp(\"test*\", \"i\") }, { \"tags\": ne         


        

Answer 1

/**
 * Adds an "or" expression to the current query.
 *
 * You can create the expression using the expr() method:
 *
 *     $qb = $this->createQueryBuilder('User');
 *     $qb
 *         ->addOr($qb->expr()->field('first_name')->equals('Kris'))
 *         ->addOr($qb->expr()->field('first_name')->equals('Chris'));
 *
 * @param array|QueryBuilder $expression
 * @return Builder
 */



/**
 * Adds an "and" expression to the current query.
 *
 * You can create the expression using the expr() method:
 *
 *     $qb = $this->createQueryBuilder('User');
 *     $qb
 *         ->addAnd($qb->expr()->field('first_name')->equals('Kris'))
 *         ->addAnd($qb->expr()->field('first_name')->equals('Chris'));
 *
 * @param array|QueryBuilder $expression
 * @return Query
 */

Answer 2

A small example in addition to theory:

Query in meta-language:

<condition1> AND (<field1 == value1> OR <field2 == value2>)

Query with Doctrine's QueryBuilder:

$queryBuilder
    ->addAnd(<condition1>)
    ->addAnd(
        $queryBuilder
            ->expr()
            ->addOr(
                $queryBuilder
                    ->expr()
                    ->field('field1')
                    ->equals('value1')
            )->addOr(
                $queryBuilder
                    ->expr()
                    ->field('field2')
                    ->equals('value2')
            )
    );