Combining `where` and `like` statements by using the CI activerecords

Question

To cut a long story short: Is it possible and if it is - how can I build a query that looks somewhat like this one

SELECT * FROM a
    WHERE row = 1 AND 
            


        

Answer 1

$this->db->where('salary_range_min >= ',$salarymin)
$this->db->where('salary_range_max <= ',$salarymax)
$this->db->where('job_title like '.$title.'% or skill like %'.$title.'%');
// OR */
$this->db->where('job_title like '.$title.'% or skill like %'.$title.'%',FALSE);
// OR */
$this->db->where('job_title like '.$title.'% or skill like %'.$title.'%',NULL);

Try this out

Answer 2

You can use the following:

$this->db->like('title', 'match', 'before');

It will produce:

WHERE `title` LIKE '%match' ESCAPE '!'

Answer 3

Why dont you try this:

    $this->db->where("row = 1 AND 
        (other_row LIKE '%..%' OR another_row LIKE '%..%')");
$this->db->get('a');

It's how you can write custom WHERE in CI. If it is not what u r looking for, feel free to explain

Answer 4

You can try this.

   $query = $this->db->select('*')
            ->from('a')
            ->where('row',1)
            ->where("(other_row LIKE '%%' OR another_row LIKE '%%' )")
            ->get();


    foreach ($query->result() as $row) {
        //do sth.
    }

You can write custom query string (from active record class)

 Custom string:
 You can write your own clauses manually:

 $where = "name='Joe' AND status='boss' OR status='active'";

 $this->db->where($where);

Answer 5

I also having problem with or_where so i simply make my custom query like

$this->db->query("SELECT * FROM `a` WHERE `row`=1 AND (CONDITION1 OR CONDITION2)")

Answer 6

$sql= "SELECT * FROM `a`
WHERE row = '1' AND 
(other_row LIKE '%" . $value . "%' OR another_row LIKE '%" . $value . "%')";
 $this->db->query($sql);