Given a jqGrid populated with local data and created with the option of idPrefix:\"custTable\" , all the generated rows get the prefix in the html id i.e. custTableRow_1 cus
The option idPrefix
was introduced to hold ids on the HTML page unique even you have on the page the ids like the rowids loaded from the server. Typical example is two grids with the data loaded from the server. Let us you have two tables in the database where you use IDENTITY or AUTOINCREMENT in the definition of the PRIMARY KEY
. In the case the primary key will be generated automatically in the table and will be unique inside the table, but there are not unique over the tables. So if you would use the primary keys as ids of the grids and place on one page two grids you can have id duplicates.
To solve the problem you can use idPrefix: "a"
as additional option in the first grid and use idPrefix: "b"
in the second grid. In the case locally jqGrid will uses everywhere ids with the prefix, but the prefix will be cut if the ids will be sent to the server.
So you will see locally in all callbacks (events) and in all methods (like setRowData
, addRowData
etc) the ids with the prefix, but on the server side the ids the prefixes will be removed immediately before sending to the server.
I recommend you additionally to read another answer about the restrictions in the ids which I posted today.
UPDATED: I looked through the code which you posed on jsfiddle and found some clear bugs in your code. You current code
1) use wrong algorithm to generate id of the new row. For example the following code
// generic way to create an animal
function newAnimal(collection, defaults) {
var next = collection.length + 1;
var newpet = {
id : next,
name: defaults.name + next,
breed: defaults.breed
};
return newpet;
}
use collection.length + 1
for the new id. It's wrong if you allows to delete the items. By adding of two items, deleting one from there and adding new item one more time follows to id duplicates. Instead of that it's more safe to use some variable which will be only incremented. You can use $.jgrid.randId() for example which code is very simple.
2) you call addRowData
with adding a prefix manually (see dogsPrefix+newdog.id
below). It's wrong because jqGrid adds the prefix one more time to the rows.
// add dog button actions
$('#dogAddAtEnd').click(function() {
var newdog = newAnimal(dogs, dogDefaults);
dogs.push(newdog);
dogAdded();
dogsTable.jqGrid('addRowData', dogsPrefix+newdog.id, newdog);
});
Probably there are more problems, but at least these problems can explain the problems which you described.
UPDATED 2: I examined new demo which you posted. It has still the lines
grid.jqGrid('addRowData', newanimal.id, newanimal,
"after", prefix+ followingId);
and
dogsTable.jqGrid('addRowData', dogsPrefix+newdog.id, newdog);
which must be fixed to
grid.jqGrid('addRowData', newanimal.id, newanimal,
"after", followingId);
and
dogsTable.jqGrid('addRowData', newdog.id, newdog);
Nevertheless I tested the demo after the changes and found bugs in code of addRowData
, delRowData
and setRowData
. The problem are in the line of the delRowData
and the same line of setRowData
var pos = $t.p._index[rowid];
can be fixed to the following
var id = $.jgrid.stripPref($t.p.idPrefix, rowid), pos = $t.p._index[id];
Inside of addRowData
I suggest to include the line
var id = rowid; // pure id without prefix
before the line
rowid = t.p.idPrefix + rowid;
of addRowData
. Another tow lines of addRowData
lcdata[t.p.localReader.id] = rowid;
t.p._index[rowid] = t.p.data.length;
should be changed to
lcdata[t.p.localReader.id] = id;
t.p._index[id] = t.p.data.length;
where unprefixed id will be used.
The modified code of you demo which uses the fixed version of jquery.jqGrid.src.js you can test here.
I will post my bug report to trirand later to inform the developer of the jqGrid. I hope that soon the bug fix will be included in the main code of jqGrid.
Additionally I recommend you to use $.jgrid.stripPref
method to strip prefixes from the rowids. For example the function
//general delete selected
function deleteSelectedAnimal(list, grid, prefix)
{
var sel = grid.jqGrid('getGridParam', 'selrow');
if (sel.length)
{
var gridrow = sel;
//get the unprefixed model id
var modelid = gridrow;
if (prefix.length !== 0)
{
modelid = modelid.split(prefix)[1];
}
// make it a numeric
modelid = Number(modelid);
//delete the row in the collection
list = RemoveAnimal(list, modelid);
//delete the row in the grid
grid.jqGrid('delRowData', gridrow);
}
}
from your demo can be rewritten to the following
//general delete selected
function deleteSelectedAnimal(list, grid)
{
var sel = grid.jqGrid('getGridParam', 'selrow'),
gridPrefix = grid.jqGrid('getGridParam', 'idPrefix');
if (sel !== null)
{
//delete the row in the collection
// ??? the gogs list will be not modified in the way !!!
list = RemoveAnimal(list, $.jgrid.stripPref(gridPrefix, sel));
//delete the row in the grid
grid.jqGrid('delRowData', sel);
}
}
I am not sure that the line list = RemoveAnimal(list, $.jgrid.stripPref(gridPrefix, sel));
or the function RemoveAnimal
do what you want, but it's not a problem which connected with jqGrid.
One more small remark about your code. You use already in the objects which you add to the grid the id
property. It's the same name as defined in the localReader.id. In the case the data from the id
property will be used as id
attribute of the grid rows (<tr>
). The local data
parameter will save the id
additionally to other properties which are build from the name
property of the items of colModel
. So I see no sense to define hidden column
{ key: true, name: 'id', align: 'left', hidden: true }
How you can see on the demo all stay works exactly as before if you remove id
column from the grids which you use.
UPDATED 3: As promised before I posted the corresponding bug report here.