I\'m running scrapy 0.20.2.
$ scrapy shell \"http://newyork.craigslist.org/ata/\"
I would like to make the list of all links to advertiseme
matches
is an XPath 2.0 function, and scrapy only supports XPath 1.0 (which does not have any regular expression support built in). You'll have to extract all the links using a scrapy selector and then do the regex filtering at the Python level rather than within the XPath.
For this special use case, there is an XPath 1.0-workaround using translate(...)
:
//a[
translate(substring-before(@href, '.html'), '0123456789', '') = ''
and @href != '.html'
and substring-after(@href, '.html') = '']
The translate(...)
call removes all digits from the name part before the .html
extension. The second line check makes sure .html
is excluded (nothing before the dot), the last makes sure .html
actually is the file extension.