So right now - my Python program (in a UNIX environment) can save files.
fig.savefig(\'forcing\' + str(forcing) + \'damping\' + str(damping) + \'omega\' + st
I am assuming that you are working with pylab
(matplotlib
).
You can use a full path as the fname
argument of savefig(fname, ...)
, which can be either an absolute path like /path/to/your/fig.png
or a relative one like relative/path/to/fig.png
. You should make sure that the directory for saving the file already exists. If not use os.makedirs
to create it first:
import os
... # create the fig
dir = 'path/to/Pics2'
if not os.path.isdir(dir): os.makedirs(dir)
fname = 'forcing' + str(forcing) + 'damping' + str(damping) + 'omega' + str(omega) + 'set2.png'
fig.savefig(os.path.join(dir, fname))
By using a full or relative path. You are specifying just a filename, with no path, and that means that it'll be saved in the current directory.
To save the file in the Pics2
directory, relative from the current directory, use:
fig.savefig('Pics2/forcing' + str(forcing) + 'damping' + str(damping) + 'omega' + str(omega) + 'set2.png')
or better still, construct the path with os.path.join()
and string formatting:
fig.savefig(os.path.join(('Pics2', 'forcing{0}damping{1}omega{2}set2.png'.format(forcing, damping, omega)))
Best is to use an absolute path:
path = '/Some/path/to/Pics2'
filename = 'forcing{0}damping{1}omega{2}set2.png'.format(forcing, damping, omega)
filename = os.path.join(path, filename)
fig.savefig(filename)
You can join your filename with a full path so that it saves in a specific location instead of the current directory:
import os
filename = "name.png"
path = "/path/to/save/location"
fullpath = os.path.join(path, filename)
Using os.path.join
will properly handle the separators, in a platform independent way.