Convert Julian Date to YYYY-MM-DD

Question

I have searched far and wide, but I can\'t seem find a way to convert julian to yyyy-mm-dd.

Here is the format of my julian:

The Julian format

Answer 1

FOR SQL Users DECLARE @jdate VARCHAR(10) SET @jdate = 117338 SELECT dateadd(dd, (@jdate - ((@jdate/1000) * 1000)) - 1, dateadd(yy, @jdate/1000, 0))

Answer 2

Edit: leaving this answer for Oracle and MySQL users
This will not work in T-SQL.

Use this:

MAKEDATE(1900 + d / 1000, d % 1000)

For example:

SELECT MAKEDATE(1900 + 95076 / 1000, 95076 % 1000)

This returns March, 17 1995 00:00:00.

SQLFiddle

Answer 3

This will definitely work in all case.

DECLARE @date int
SET @date = 21319
SELECT DATEADD(dd, RIGHT(@date,LEN(@date)-3)-1, DATEADD(yy,LEFT(@date,1)*100 +RIGHT(LEFT(@date,3),2),'1 Jan 1900'))

Answer 4

Standard SQL is simple (you can do similar for 2 digit year YYMMDD)

Declare @julDate int = 2020275

Select 
DateAdd
(
   day
   , Right(@julDate,3)-1
   , Cast((Left(@julDate,4)+'-01-01') as smalldatetime)
)

Answer 5

Declare @Julian varchar(7)

Declare @date date

Set @Julian = 2020277

Set @Date = Dateadd(day,+ Cast(right(@Julian,3) as int)-1, Cast(left(@Julian,4) + '0101' as Date))

Select @Date

Answer 6

You need to specify 1 or 0 for century in first character. For example, SET @date = 21319 should be prefixed with 1 or 0. Below is an example that will work with all y2k use cases.

DECLARE @jdate INT 
SET @jdate = 119150 
SELECT DATEADD(dd, (@jdate - ((@jdate/1000) * 1000)) - 1, DATEADD(yy, @jdate/1000, 0))