Javascript object group by day,month,year

Question

I am working on application which I need to do grouping of different sets of javascript object and those will be based on month,day and year.

For day I am doing like

Answer 1

Please see if the following refactor is useful for you http://jsfiddle.net/wkUJC/

var dates = [{"2012-12-02T00:00": 2000}, {"2013-01-01T00:00": 1200},{"2013-02-02T00:00": 550}, {"2013-02-02T00:00": 1000}];

function calc(dates) {
    var response = {};
    dates.forEach(function(d){
        for (var k in d) {
            var _ = k.split("-");
            var year = _[0]
            var month = _[1]
            if (!response[year]) response[year] = {total: 0}
            response[year][month] = response[year][month] ? response[year][month]+d[k] : d[k]
            response[year].total+= d[k]
        }
    });
    console.log(response);
    return response;
}

calc(dates);

Answer 2

Given a slightly different structure of data:

var data = [{
  "date": "2011-12-02T00:00",
  "value": 1000
}, {
  "date": "2013-03-02T00:00",
  "value": 1000
}, {
  "date": "2013-03-02T00:00",
  "value": 500
}, {
  "date": "2012-12-02T00:00",
  "value": 200
}, {
  "date": "2013-04-02T00:00",
  "value": 200
}, {
  "date": "2013-04-02T00:00",
  "value": 500
}, {
  "date": "2013-03-02T00:00",
  "value": 500
}, {
  "date": "2013-04-12T00:00",
  "value": 1000
}, {
  "date": "2012-11-02T00:00",
  "value": 600
}];

You could use underscore:

var grouped = _.groupBy(data, function(item) {
    return item.date;
});

var groupedByYear = _.groupBy(data, function(item) {
    return item.date.substring(0,4);
});

var groupedByMonth = _.groupBy(data, function(item) {
    return item.date.substring(0,7);
});

console.log(groupedByYear);

See related answer: Javascript - underscorejs map reduce groupby based on date