Grep regular expression not working as expected

Question

I have a simple grep command trying to get only the first column of a CSV file including the comma. It goes like this...

grep -Eo \'^[^,]+,\' so         


        

Answer 1

BSD grep is buggy in general. See the following related posts:

• Why does this BSD grep result differ from GNU grep?
• grep strange behaviour with single letter words
• How to make BSD grep respect start-of-line anchor

That last link above mentions your case: when -o option is used, grep ignores the ^ anchor for some reason. This issue is also described in a FreeBSD bug:

I've noticed some more issues with the same version of grep. I don't know whether they're related, but I'll append them here for now.

$ printf abc | grep -o '^[a-c]'

should just print 'a', but instead gives three hits, against each letter of the incoming text.

As a workaround, it might be a better idea to just install GNU grep that works as expected.

Or, use sed with a BRE POSIX pattern:

sed -i '' 's/^\([^,]*,\).*/\1/' file

where the pattern matches

• ^ - start of a line
• \([^,]*,\) - Group 1 (later referred to with \1 backreference from the RHS):
  • [^,]* - zero or more chars other than ,
  • , - a , char
• .* - the rest of the line.

Note that -i will change the file contents inplace. Use -i.bak to create a backup file if needed (then, you wouldn't need the next empty '' though).