As I am rather new to R, I am trying to learn how I can extract two values from a XML file and loop over 5603 other (small, <2kb) XML files in my working directory.
This might work for you. I got rid of the for
loop and went with sapply
.
xmlfiles <- list.files(pattern = "*.xml")
txtfiles <- gsub("xml", "txt", xmlfiles, fixed = TRUE)
txtfiles
is a set of new file names to be used as the output file for each run.
sapply(seq(xmlfiles), function(i){
doc <- xmlTreeParse(xmlfiles[i], useInternal = TRUE)
zipcode <- xmlValue(doc[["//ZipCode"]])
amount <- xmlValue(doc[["//AwardAmount"]])
DF <- data.frame(zip = zipcode, amount = amount)
write.table(DF, quote = FALSE, row.names = FALSE, file = txtfiles[i])
})
Please, let me know if there are issues when you run it.
Slightly different approach to Richard's (only slightly). Used ldply
to make a data frame before writing it out to a file. You should select his for the answer since the "guts" of the ldply
function is his, but this just shows an alternate way of doing it (assuming you want one file vs many files):
setwd("LOCATION_OF_XML_FILES")
xmlfiles <- list.files(pattern = "*.xml")
dat <- ldply(seq(xmlfiles), function(i){
doc <- xmlTreeParse(xmlfiles[i], useInternal = TRUE)
zipcode <- xmlValue(doc[["//ZipCode"]])
amount <- xmlValue(doc[["//AwardAmount"]])
return(data.frame(zip = zipcode, amount = amount))
})
head(dat)
## zip amount
## 1 442420001 45000
## 2 479072114 400580
## 3 303320420 22050
## 4 326112002 12000
## 5 265066845 37000
## 6 168027000 300000
write.csv(dat, "zipamount.csv", row.names=FALSE)
You could use append=TRUE
with Richard's approach and use a single file name in that write.table
to do the same thing. You can also tweak the output settings of write.csv
(or write.table
) to get the output format you eventually want to work with.
You can also add recursive = TRUE
to the list.files
to go through all the subdirectories vs put all ~5,600 files into one directory (that can have performance issues on some filesystems/operating systems).